Perturbation Theory (Non-Degenerate)

jhosamelly
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If I have V(x)=\frac{1}{2}m\omega^{2}x^{2} (1+ \frac{x^{2}}{L^{2}})

How do I start to solve for the hamiltonian Ho, the ground state wave function ?? Calculate for the energy of the quantum ground state using first order perturbation theory?
 
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H= H_{0} + H_{p}

So basically, you have an aditional term, H_{p} = \frac{1}{2L^{2}}mω^2 x^4, that perturbates your hamiltonian.
You already know the solution for the harmonic oscillator, H= H_{0} = \hbarω(n + \frac{1}{2}), so you just have to find the corrections for the H_{p}.

hope i made myself clear ( ;
 
so does this mean my hamiltonian would be H= \hbarω(n + \frac{1}{2}) + \frac{1}{2L^{2}}mω^2 x^4 ?
 
Don't you know the ground state wave function of unperturbed oscillator.you can see them elsewhere and then just evaluate(with normalized eigenfunctions)
<E>=∫ψ0*(Hp0
 
I actually don't know the wave function.. That's also my prob... if i only know the wave function I'll be able to solve this.
 
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Is this the same for an anharmonic oscillator? That is the problem about.
 
No,you use unpertubed harmonic oscillator wave function for calculation.
 
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