JesseM
Science Advisor
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What does "actually simultaneous" even mean? No one is claiming that there is any absolute simultaneity involved, each frame uses its own distinct definition of simultaneity, and all frames are equally valid as far as physics goes. "Preferred frame" is used to denote the notion of a frame where the laws of physics take a different, preferred form than in other frames (like in the old aether theories where light would only move at c in all directions in the rest frame of the aether, in other frames its speed would be different in different directions), but I'm in no way using such a preferred frame. The whole argument about tachyons is based on the idea that the laws of physics governing tachyons should work the same way in every frame, so if you can show that tachyons move instantaneously or backwards in time in terms of one frame's definition of simultaneity, it must be possible for tachyons to move instantaneously or backwards in time in terms of every frame's definition of simultaneity. If you deny this, and say tachyons can behave this way in some frames but not others, then it is you who are postulating a preferred frame!RandallB said:No this is not what simultaneity means!
Any one frame can ignore all other frames and show separated simultaneous events and get usable answers as long as it never uses a value defined in some other frame. Simultaneity says that the simultaneous space like separated results you find using such a “preferred frame” cannot be understood as actually being simultaneous.
What does "actually being simultaneous" mean? If you're suggesting that there is some absolute truth about whether events are simultaneous, which is different from the definition of simultaneity used by a particular frame, that's the opposite of what Einstein was trying to show. If you're just saying that there is no absolute definition of simultaneity, that we can only talk about "simultaneity" relative to a particular frame but that all frames are equally valid, then I agree entirely, that's what I've been saying all along. And if you combine that with the first postulate which says the laws of physics must work the same way in every frame, then if it's possible to send tachyon signals which move instantaneously or backwards in time according to one frame's definition of simultaneity, then it must be possible to send tachyon signals which move instantaneously or backwards in time according to any other frame's definition of simultaneity too.RandallB said:Sure even Einstein uses the word simultaneous within individual frames for SR speed problems such as trains and embankments. That is how he illustrated getting to the conclusion that simultaneous events in one frame were not simultaneous in the other frame. Likewise simultaneous events in the other frame were shown to not be simultaneous in the first.
From that Einstein established the principle of simultaneously, in order to maintain a consistent set of physics laws usable in all frames of reference. The simple rule of simultaneity is that simultaneous events within a single reference frame cannot be considered as actually being simultaneous - That's It!
What are you talking about? I never said anything about absolute values. I just said when the tachyon departs and when it arrives using a particular frame's coordinate system.RandallB said:Now you and Jesse seem to think that simultaneity can be used to identify the correct time for tachyon in absolute values well enough to when it reached a distant point to know realtive to local time.
What do you mean by "local time" anyway? Do you mean something different than "the time in a particular frame"? After all, frames of reference in SR are not "local" to a particular region, they are coordinate systems that describe events throughout the entirety of spacetime.
Yes, that's right, x' = gamma*(x - vt) = 1.25*(5 - 0.6*8 1/3) = 1.25*(5 - 5) = 0RandallB said:If either of you could do that, then I have simple challenge one of you should be able to solve – no tachyon needed. If you can do it for tachyons, this should be easy.
Use Jesse’s problem where the other frame moves at 0.6c with observers at x= 0 & 10 and x’ = 0 & 5.
Do the math to be sure we all agree on the fallowing three sets of truly simultaneous events based on SR simultaneity rules:
A: x = 0 correctly observes a flash of light (following the tachyon) start off at t=0
simultaneously x’ = 0 sees the same flash start at t’=0
B: x =5 meets x’ =0 at t=8 1/3
Yes, it's correct that x'=0, t'=6 2/3 in the primed frame has spatial coordinate x=5 in the unprimed frame, since:RandallB said:simultaneously x’= 0 meets x = 5 at t’ = 6 2/3
x = gamma*(x' + vt') = 1.25*(0 + 0.6*6 2/3) = 1.25*4 = 5. And it's also true that
t = gamma*(t' + vx'/c^2) = 1.25*(6 2/3 + 0.6*0) = 8 1/3.
So, all you're really saying here is that the event with coordinates (x=5, t=8 1/3) in the unprimed frame has coordinates (x'=0, t'=6 2/3) in the primed frame. These aren't two simultaneous events, it's just a single event that is assigned different coordinates in the two coordinate systems.
Again, this is just the same event assigned different coordinates in the two coordinate systems, not two simultaneous events...but yes, your numbers are correct again.RandallB said:C: x = 10 sees the flash of light arrive at t = 10
simultaneously x’ = 5 sees the same flash arrive at t’ = 5
Sure. What's the problem here? Since B and C are spacelike separated (neither event lies within the other event's light cone), different frames can disagree on which event happened first and which happened second. That's just a standard feature of relativity. However, without tachyons no physical signal can travel between B and C, so there's no frame that sees information going FTL or backwards in time.RandallB said:When did the simultaneous C events occur before or after simultaneous B events ?
Observer x = 5 claims before as do all other x observers while x’=0 claims after as do all other x’ observers!
I don't understand what you mean by "solve this". It's an accepted fact that because different frames disagree about simultaneity, they can also disagree about which of two spacelike separated events happened earlier and which happened later. Do you disagree that this is an accepted fact? If you do disagree, I can quote various sources on SR which point this out. And if you agree that this is widely accepted, then again, what's the problem?RandallB said:If either of you can solve this using SR and simultaneity, without a preferred reference frame. I will issue an apology and a retraction.
Again, if you think I'm claiming there's some sort of absolute truth about simultaneity, you've got my argument completely backwards. Simultaneity is relative to one's choice of reference frame. For any single tachyon signal, different frames disagree about whether it's going forward in time or backward in time, and there is no absolute truth about this. The point is that if you have a frame A where a tachyon signal is going FTL but forwards in time and another frame B where it's going backwards in time, then by the principle that anything which is physically possible in one frame must be physically possible in all frames (the first postulate of relativity), it must be possible to send a second tachyon signal in reply to the first which is going FTL but forwards in time in frame B, and backwards in time in frame A. With the combination of the two signals, you can arrange things so that the event of an observer receiving the reply actually happens in the past light cone of the event of the same observer sending the original tachyon signal, so in this case all frames agree that the reply was received before the first signal was sent (these two events have a timelike separation rather than a spacelike one, meaning there can be no disagreement about their order).RandallB said:But I expect an unambiguous definitive answer for one or the other before or after!
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