Numerical Analysis: Uniform Continuity Question

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SUMMARY

The discussion centers on proving that a function is uniformly continuous on an open interval (a,b) by first establishing uniform continuity on the closed interval [a,b]. It is confirmed that if a function is uniformly continuous on [a,b], it is also uniformly continuous on the open interval (a,b). This conclusion is grounded in the properties of continuous functions and their behavior on closed versus open intervals.

PREREQUISITES
  • Understanding of uniform continuity and its definition.
  • Familiarity with continuous functions on closed intervals.
  • Knowledge of the properties of open and closed intervals in real analysis.
  • Basic concepts of limits and convergence in calculus.
NEXT STEPS
  • Study the formal definition of uniform continuity in real analysis.
  • Explore examples of uniformly continuous functions on closed intervals.
  • Investigate the implications of the Heine-Cantor theorem.
  • Learn about the relationship between continuity and uniform continuity in various contexts.
USEFUL FOR

Students of mathematics, particularly those studying real analysis, as well as educators and anyone interested in the properties of continuous functions and their applications in mathematical proofs.

The_Stix
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This isn't so much of a homework problem as a general question that will help me with my homework.

I am supposed to prove that a given function is uniformly continuous on an open interval (a,b).

Since for any continuous function on a closed interval is uniformly continuous, I am curious if I can prove that the function is uniformly continuous on [a,b], then it is also uniformly continuous on (a,b).

Thanks!
 
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The_Stix said:
This isn't so much of a homework problem as a general question that will help me with my homework.

I am supposed to prove that a given function is uniformly continuous on an open interval (a,b).

Since for any continuous function on a closed interval is uniformly continuous, I am curious if I can prove that the function is uniformly continuous on [a,b], then it is also uniformly continuous on (a,b).

Thanks!

Yes.
 

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