Calculating Eye Resolution at Different Distances

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To calculate the resolution of the human eye at different distances when observing two lines 0.25mm apart, one must vary the distance until the lines merge into one. The distance at which this occurs, noted as 'd', allows for the calculation of angular resolution using the formula (sin(a) = 0.25/d). The angular resolution indicates the minimum angle at which the eye can distinguish between the two lines. Additionally, the actual width that can be resolved is determined by the formula width = (distance to object) x sin(a). The discussion also touches on eye resolution variations among different animals and the impact of lighting conditions on resolution.
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hey how would you work out resolution of an human eye at defeerent distances looking at 2 lines 0.25mm apart?


cheers alex
 
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I guess you just vary the distance of your eye to the two lines, starting from a point where you can see the 2 lines distinctly. The exact point where the two lines seem to merge and you cannot see the space between them, you note this distance ,d. Since d is very large compared to the width, the angle between the 2 lines is approx (sin(a) = 0.25/d)

The angular resolution of the eye would therefore be (a) That is, you can only see distinctly a width that sweeps out an angle (a) or more from where you are standing.

hope this helps.
 
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if you want the resolution in terms or the actaul width of the object you are observing, it is width= (distance of your eye to object) x sin(a) which you found earlier.
 
Eye resolutions for various animals.
 

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ne1 kno much about resolution when u change the lux in the surroundings?
 
kmarinas86 said:
Eye resolutions for various animals.
Unfortunately, my eye resolution isn't good enough for me to read that. :frown:
 
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