Andrew,
Mute,
The (isothermal) equilibrium of chemical reactions at high (enough) temperatures is determined by the variation of entropy. Indeed
DG = DH - T DS
and for high temperatures the entropy term (DS) will dominate. This explains for example why transformation from solids to gas phase are preferred at higher temperatures.
The variation of entropy can be calculated by cumulating from a reference temperature:
DS(T) = DS(T0) + [DS(T) - DS(T0)]
The last term, [DS(T) - DS(T0)], can be calculated from specific heats and latent heats.
Eventually, the first term can be taken at the absolute zero temperature.
From this, clearly, we don't need the entropy S(0) of each reactant. But, clearly also, we need DS(0), the absolute reaction entropy at the absolute zero temperature. From the third law we must assume that DS(0) = 0. Therefore, the question of the absolute entropy for individual substance maybe somewhat theoretical but is seems practical at least for (absolute) reaction entropies.
So, I am left with some difficulties:
how can we be sure that DS(0) = 0
and what is the physical basis
should we take that as a principle (3rd principle), partly based on observations
what are the observations
and: can absolute entropy variations be measured, and how
Thanks already for your discussion,
Michel
Post-scriptum:
===========
I find the Jaynes point-of-view quite natural.
It is clear that the preparation of a system determines its behaviour.
Therefore, by extension, entropy should not only be associated to a thermodynamic (equilibrium) state of a system but simply to any prepared state of system included the less prepared one: the thermodynamic equilibrium.
For equilibrium thermodynamics, it is not surprising that the property of a system preparation (known, knowledge) becomes the property of a system.