Relationship between current, drift velocity and thermal velocity

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In a solid cylindrical resistor like copper at room temperature, the drift velocity of conduction electrons is directly proportional to the current flowing through the conductor. The thermal velocity of these electrons is influenced by temperature, with a formula of sqrt(3kT/m) indicating it reaches around 10^5 m/s at room temperature. While the drift velocity and current are linked through the equation I = vnqA, where n is electron concentration, q is charge, and A is cross-sectional area, the thermal velocity remains largely unaffected by current changes. The current density can be expressed as J = vnq, establishing a relationship between particle flux and electron concentration. Overall, the interplay between current, drift velocity, and thermal velocity is crucial for understanding electron behavior in conductors.
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for a normal solid cylindrical resistor, made of say copper, at room temperature, describe the relationshop between the current in the conductor, the drift velocity of conduction electrons in the conductor, and the thermal velocity of conduction electrons in the conductor.
 
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The drift velocity and current are proportional. The thermal speed depends on the temperature. Current is not much affected.
 
could u give a formula pls
 
The thermal energy is 3/2 kT, so equating that to kinetic energy, thermal velocity is sqrt(3kT/m), on the order of 10^5 m/s at room temperature.

The drift velocity is related to current like I = vnqA, where n is the concentration (per volume), of electrons, q is the charge. In terms of current density, J = vnq. Current density is charge per second per area, so dividing both sides by q relates a particle flux on the left hand side to a concentration times a velocity on the right. This is a general relationship in kinetics.
 
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