Calculating Stoichiometric Ratios for Chemical Reactions

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To determine the moles of aluminum needed to produce 3.4 moles of aluminum oxide, the balanced equation 4Al + 3O2 --> 2Al2O3 is essential. The correct stoichiometric ratio for aluminum to aluminum oxide is 4 moles of Al for every 2 moles of Al2O3. Using this ratio, the calculation can be set up as 4:2 = x:3.4, allowing for the determination of x, the required moles of aluminum. Factor labeling or dimensional analysis can aid in converting units effectively. Understanding stoichiometric calculations is crucial for solving such problems.
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HELP! I've been having problems with Chemistry the past semester and a half, but stoichiometry is the hardest thing yet. Here's the problem:

Aluminum oxide is formed from the reaction of metallic aluminum with oxygen gas. How many moles of Aluminum are needed to form 3.4 moles of Aluminum oxide?

I've looked around the site and found a thread on it, but it didn't help me completely. So far, I have the balanced equation: 4Al + 3O2 --> 2Al2O3. The ratio is 4/3, but where do I go from there?
 
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Have you ever used factor labeling before? It is also known as dimensional analysis.

http://www.bcpl.net/~kdrews/factorlabel.html

using this idea you can convert the units of 3.4 moles of aluminum oxide to aluminum using the ratio 4 moles of aluminum/ 2 moles of aluminum oxide. (In otherwords for each mole of aluminum oxide you wish to create you need 2 of aluminum)
 
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Ratio of 4/3 is not the one you are asked about.

If 4 moles of Al gives 2 moles of oxide, how many moles of Al (x) are needed to produce 3.4 mole of oxide?

4:2 = x:3.4

Solve for x.

Read about stoichiometric calculations.
 
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