Stiochemistry practice problems help

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SUMMARY

The discussion focuses on calculating the number of moles of aluminum required to produce 3.4 moles of aluminum oxide (Al2O3) based on the balanced chemical equation 4Al + 3O2 --> 2Al2O3. It is established that 4 moles of aluminum yield 2 moles of aluminum oxide, leading to the conclusion that the ratio of aluminum to aluminum oxide is 2:1. Therefore, to produce 3.4 moles of Al2O3, 6.8 moles of aluminum are necessary.

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  • Understanding of stoichiometry and mole ratios
  • Familiarity with balancing chemical equations
  • Knowledge of the concept of moles in chemistry
  • Basic algebra skills for setting up ratio equations
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  • Learn about mole-to-mole conversions using balanced equations
  • Practice additional stoichiometry problems involving different compounds
  • Explore the concept of limiting reactants in chemical reactions
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Homework Statement



Aluminum oxide is formed from the reaction of metallic aluminum with oxygen gas. How many moles of Aluminum are needed to form 3.4 moles of Aluminum oxide?

Homework Equations



first equation:Al + O2 --> Al2O3 i balanced it at 4Al + 3O2 --> 2Al2O3

The Attempt at a Solution



okay I just really need help understanding this because I have no clue what I am doing and don't understand how to work the problem! please help:confused:
 
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Ok, so you've balanced your equation correctly. From this you know that 4 moles of aluminium produce 2 moles of aluminium oxide, and want to calculate the number of moles of Al required to produce 3.4 moles of aluminium oxide (x, say).

1. What is the ratio of Al to Al2O3?
2. Can you set up a ratio equation for x?
 

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