What do 'perfect elastic' and 'perfect inellastic' collision mean?

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Discussion Overview

The discussion revolves around the definitions and implications of perfect elastic and perfect inelastic collisions, exploring whether such collisions can truly exist or are merely theoretical constructs. The conversation also touches on related concepts of conservative forces and their mathematical characterization, although this strays from the original topic of collisions.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested

Main Points Raised

  • Some participants define a perfect elastic collision as one where kinetic energy is conserved, while a perfect inelastic collision results in the colliding objects sticking together, with some kinetic energy converted to other forms of energy.
  • One participant asserts that perfectly elastic collisions do exist, but primarily at the particle level, noting that macroscopic objects always lose some energy to noise and heat.
  • Another participant introduces the concept of conservative forces, stating that a force is conservative if the work done is independent of the path taken.
  • There is a discussion about the mathematical condition for a force to be conservative, specifically referencing the curl of the force vector.
  • One participant expresses concern that the discussion has deviated from the original question about elastic collisions to a more complex topic involving mathematical properties of forces.
  • Another participant emphasizes that physics explanations can often be conveyed without mathematics, suggesting that a conservative force can be understood in terms of potential energy and mechanical work.

Areas of Agreement / Disagreement

Participants express differing views on the existence of perfect elastic collisions, with some supporting their existence at the microscopic level while others highlight the practical limitations at macroscopic scales. The discussion on conservative forces introduces additional complexity, with no clear consensus on the appropriateness of mathematical explanations in the context of the original question.

Contextual Notes

The discussion includes unresolved mathematical aspects regarding the characterization of conservative forces, particularly concerning the conditions under which certain force functions may not be conservative due to discontinuities.

kthouz
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What does mean a perfect elastic collision and a perfect inellastic collision? Do they really exist or it is just by assuming?
 
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In an elastic collision kinetic energy is conserved. In an inelastic collision the two colliding things form a new unique object (they stay glued together), and some of the kinetic energy is transformed in other forms of energy (usually heat).

Perfectly elastic collisions exist, but not with macroscopic objects. There is always some energy lost to noise and heat. But at particle level (molecules, atoms, electrons, etc.) most of the collisions are perfectly elastic.
 
conservative force.

How to find mathematically that a force is conservetive? i know by definition that a conservative force is a force in which work done is indipendent of the path followed like gravitational force.
 
if we know the function of the force , and [tex]\nabla \times F=0[/tex]

then it is conservetive
 
but i don't know, kthouz,whether you are a college student.

if not, just remember the friction isn't
 
enricfemi said:
if we know the function of the force , and [tex]\nabla \times F=0[/tex]

then it is conservetive

What about

[tex]F \left( x , y , z \right) = \frac{-y}{x^2 + y^2} \hat{x} + \frac{x}{x^2 + y^2} \hat{y}?[/tex]

:rolleyes:
 
George Jones said:
What about

[tex]F \left( x , y , z \right) = \frac{-y}{x^2 + y^2} \hat{x} + \frac{x}{x^2 + y^2} \hat{y}?[/tex]

:rolleyes:

What about [tex]x=y=0[/tex]?

[tex]\nabla\times F= 0[/tex] except for [tex]x=y=0[/tex]

The function has a discontinuity for [tex]x=y=0,\,\,\, F=\infty[/tex]
For any closed path that does not enclose the origin, any line integral of the function is zero.

Happily, in physics you don't often find functions with poles.

Anyhow, I don't think that this thread is the good one to talk about curls and discontinuities.

It is better to stick to the original question and to the level of the question. Talk about curls to someone who asks about elastic collisions is not a good idea. There are other ways to explain what is a conservative force.
 
alright,alright, so talk about how to explain conservetive force mathematically
without curls.
 
This is a physics forum. In physics you do not need mathematics to explain anything. You explain without math and, once it has been understood, you use the math to calculate.

I can assure you that, in physics if you need math to explain something, it means that you have not well understood the subject.

A conservative force is a force whose exerted work is converted in potential energy which can be transformed back completely into mechanical work.
 

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