Circular motion/gravitational force implied

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The discussion revolves around a problem involving a body at height h above a planet, seeking to determine the impulse needed to set it in circular motion around the planet. The initial approach involves equating centripetal force (Fc) to gravitational force (Fg) to find the required velocity. The solution reveals that the velocity can be calculated using the formula √(GM/r), where G is the gravitational constant, M is the mass of the planet, and r is the distance from the planet's center to the body. The participant expresses relief at discovering a simpler solution than anticipated. This highlights the importance of understanding the relationship between forces in circular motion and gravitational attraction.
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Homework Statement


I've thought about a problem that I invented but couldn't solve it. So I'd like a very little help, something that can push me in the good direction but not the full answer.
Suppose we have a system that is composed of a planet and a body. The body is at an height h from the center of the planet (of course h is greater than r). Initially the body is at rest. What is the impulse we have to apply on this body in order to make it move in such a way so that it describes a circular path around the planet? Give the answer in terms of m (the mass of the body), R (distance between the center of the planet and the body), M the mass of the planet and so on. With the impulse, I can then calculate the velocity it must have to accomplish this task.
Thank you!


Homework Equations





The Attempt at a Solution


I've tried a few things, but I'm at a loss.
 
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If you are looking for velocity you can easily get it if you have M (big mass) and the h

to do that make Fc=Fg and isolate v :)
 
Thanks a bunch Epsillon! I had been stuck for a few days and I just can't believe I missed such a simple answer. I thought it would have been much more complicated. I didn't realize that I could get rid of the centripetal acceleration by considering that it's equal to the velocity squared over r.
So finally I found that the velocity is worth \sqrt{\frac{GM}{r}}.
 
You got it!
 
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