When is the Jacobian of a function a diagonal matrix

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SUMMARY

The Jacobian matrix J(f) for the function f(x,y,z) = (exp(x), cos(y), sin(z)) is computed as J(f) =
(e^x 0 0)
(0 -sin(y) 0)
(0 0 cos(z)), which is indeed a diagonal matrix. The diagonal structure arises from the independence of the component functions, where the derivatives with respect to different variables yield zeroes off the diagonal. In general, the Jacobian J(g) of a function g(x,y,z) will be a diagonal matrix when the partial derivatives of the component functions with respect to different variables are zero.

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Homework Statement


Let f(x,y,z)=(exp(x),cos(y),sin(z)).Compute the Jacobian J(f) of f . In general ,when will the Jacobian J(g) of a function g(x,y,z) be a diagonal matrix ?


Homework Equations





The Attempt at a Solution


I am not quiet sure about this question
for J(f) i found that
(e^x 0 0)
(0 -siny 0)
(0 0 cosz)
and i think this is already a diagonal matrix
 
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Your Jacobian looks fine to me. The second question was "In general ,when will the Jacobian J(g) of a function g(x,y,z) be a diagonal matrix ?"

What was it about the component functions that gave you all those zeroes off the diagonal?
 

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