What Is the Probability of Age-Related Onset for a Disease?

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The discussion centers on a statistics problem involving the normal distribution of disease onset ages, with a mean of 11 years and a standard deviation of 2 years. The user seeks help calculating probabilities for a child diagnosed with the disease, specifically for ages between 9.5 and 15.5, over 11 years, and under 10 years. Responses emphasize the importance of understanding the standard variable (z-score) and using a normal distribution table to find the required probabilities. There is a suggestion that the user should consult their teacher for better understanding rather than relying solely on forum assistance. The conversation highlights the educational value of solving such problems independently.
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hello i really have a problem in my statistic class. please help me
i'm begging you, i don't want to fail. please.. please
the problem is...

suppose the ages at time of onset of a certain disease are approximately normally distributed with a mean of 11 years and a standard daviation of 2 years. A child has just come down with the isease. What is the probability that the child is:
a) between the ages of 9.5 and 15.5 years?
b) Over 11 years of age?
c) Under 10?

it's just one problem please solve it for me
please..
shahi
freshmen student
 
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How is our solving this one problem going to help you? It would be much better for you to go to your teacher. The last thing in the world you want to do is to trick your teacher into thinking you know the subject better than you do!
(By the way, this should be posted in the homework section and you should show us what you have tried.)

In this problem, as in any "normal distribution" problem, the first thing you do is find the "standard variable": z= (x- mean)/standard deviation. In this problem you are told that the mean is 11 and the standard deviation is 2:

a) between the ages of 9.5 and 15.6 years"
translates into z= (9.5-11)/2= -0.75 and z= (15.5- 11)/2= 2.25.
Consult a table of the standard normal distribution (There should be one in your text. If not, there is a nice one at http://people.hofstra.edu/faculty/Stefan_Waner/RealWorld/normaltable.html ) to find the probability that z is between -0.75 and 2.25.

b) Over 11 years of age?
That's easy! 11 is the mean. What percentage of any normal population is above the mean? (Of course, that translates to z= 0.)

c) Under 10?
This translates to z= (10-11)/2= -0.5. Find the probability that z is less than -0.5.
(Most tables of the standard normal distribution have only positive z, saving space, since the distribution is symmetric. The probability that z< -0.5 is exactly the same as the probability that z> 0.5. To find the probability -0.75< z< 2.25, find the probability that 0< z< 0.75, the probability that 0<z< 2.25 and add.)
 
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