Can a 10A Fuse Handle a 150W Radio and 240V Water Heater in Parallel?

AI Thread Summary
A 10A fuse can handle the simultaneous use of a 150W radio and a 240V water heater with a resistance of 40Ω. The current drawn by the radio is calculated to be 0.625A, while the heater draws 6A. The total current required for both devices is 6.625A, which is below the 10A limit of the fuse. Therefore, the fuse will not blow under these conditions. The calculations confirm that the setup is safe for use.
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Homework Statement


A radio (power = 150 W) and a water heater (resistance = 40 Q) are connected in
parallel. The current, needed for them is fused at 10 A maximum.

Homework Equations


Does the fuse stand the simultaneous use of the radio and the heater? The voItage is 240 V.

The Attempt at a Solution


r: radio
h: heater

V=Vr=Vh
Itotal=Ir+Ih

Pr=V*Ir
Ir=150/240=0.625 ampere

Vh=R*Ih
Ih = Vh/R = 240/40 = 6 amperes

Itotal = 0.625+6 = 6.625
6.625<10 so the fuse will stand
 
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That looks good.
I guess the "40Q" meant "40Ω".
 
Delphi51 said:
That looks good.
I guess the "40Q" meant "40Ω".
yesyes 40Ω , and thank you o:)
 

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