Combining Newton's Laws: Solving for Acceleration and Moment of Inertia

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SUMMARY

This discussion focuses on combining Newton's laws to derive the equation mg = I/R^2*a, where T represents torque, I is the moment of inertia, alpha is angular acceleration, m is mass, g is the gravitational constant, and a is linear acceleration. The user successfully eliminates variables alpha and T from the equations TR = I(alpha) and T - mg = ma, leading to a simplified relationship. The derivation involves recognizing that R^2 arises from the centripetal acceleration formula v^2/r, which is integrated into the context of rotational motion.

PREREQUISITES
  • Understanding of Newton's laws of motion, specifically the second law for both linear and rotational motion.
  • Familiarity with the concepts of torque (T), moment of inertia (I), and angular acceleration (alpha).
  • Knowledge of centripetal acceleration and its relationship to angular motion.
  • Basic algebra skills for manipulating equations and understanding variable relationships.
NEXT STEPS
  • Study the derivation of the moment of inertia for various shapes and its implications in rotational dynamics.
  • Learn about the relationship between linear and angular acceleration, specifically how they are connected through radius (R).
  • Explore applications of Newton's laws in real-world scenarios, particularly in mechanical systems involving rotation.
  • Investigate the concept of torque and its role in rotational equilibrium and dynamics.
USEFUL FOR

Students of physics, mechanical engineers, and anyone interested in understanding the principles of rotational motion and dynamics through the lens of Newton's laws.

Alkatran
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I have the following problem that I can't seem to solve.

Combine these two equations:
TR = I(alpha) *Newton's 2nd law of Rotation for the wheel
T - mg = ma *Newton's Second law for the mass
to make this one:
mg = I/R^2*a

Note that a is much smaller than g

I break it to:

mg = I(alpha)/r - ma or I(alpha)/r ... unless (alpha) = a/r in which case ... hmmm

First of all I notice that alpha and T are eliminated. Two variables gone for two equations?? (a is smaller than g, does that mean alpha is...?)

Also, where does R^2 come from?

I think T if force (F), R is radius (r)
I is moment of inertia, alpha is angular accel, m is mass, g is (duh) gravitational constant and a should be acceleration
 
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I couldn't remember what "I" is defined as in terms of algebraic expression.

But "R^2" comes from acentripedal = v^2/r = alpha; after you combine

mg = ma - Ialpha/r, you plug in v^2/r for alpha, you get /r^2
 

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