rlduncan said:
Yes I disagree, as stated in earlier post. Bell's theorem like any theorem can never be violated under the conditions of the theorem. It only takes one counter example to disprove a theorem.
But your counter example must actually match the conditions of the theorem! You can't give a counter example where Alice and Bob are not guaranteed to get the same outcome if they make the same measurement, for example, as your second example involving a1 and a2 seems to do (see below).
Also note that Bell's theorem is a
statistical theorem, so random violations are actually quite possible, the idea is just that in the limit as the number of trials goes to infinity the probability of the inequality being violated approaches zero, a counterexample would have to provide some sort of rule for generating outcomes (in a local realist way) where you can
reliably get violations even as the number of trials becomes large.
rlduncan said:
If any of the sample statistics violate the theorem then the theorem is disproved or the conditions of the theorem have not been adhered to. I am suggesting the latter is true. In my original post I stated that his theorem is a mathematical truth, a tautology meaning it is always true.
If you think that's the case then you don't understand it very well, Bell is
not simply making the claim that for a set of objects which each either have or don't have properties A,B,C, we must have Number(A, not B) + Number(B, not C) ≥ Number(A, not C). That would indeed be a mathematical tautology, but it is
not Bell's theorem. Bell's theorem deals with probabilities of measurement outcomes, not simply objective (but unknowable) truths about the unmeasured hidden variables associated with all particles. Bell's theorem would be more like a derivation of this inequality:
P(measured that particle 1 had A, particle 2 did not have B
given that we measured particle 1 for A, and particle 2 for B)
+
P(measured that particle 1 had B, particle 2 did not have C
given that we measured particle 1 for B, and particle 2 for C)
≥
P(measured that particle 1 had A, particle 2 did not have C
given that we measured particle 1 for A, and particle 2 for C)
This one is obviously
not a tautology, you need a number of additional conditions to derive it. And of course we don't measure "probabilities" directly, we only measure fractions of trials where some event occurred, so what Bell's theorem is telling us is that in a situation that matches his conditions, the probability approaches zero that we would get a violation of this inequality:
(Number of trials where particle #1 was measured for property A and it
did have A, and particle #2 was measured for property B and it
did not have B)
+
(Number of trials where particle #1 was measured for property B and it
did have B, and particle #2 was measured for property C and it
did not have C)
≥
(Number of trials where particle #1 was measured for property A and it
did have A, and particle #2 was measured for property C and it
did not have C)
You can of course have violations of this in a small number of measurements, but if the setup of the experiment matches Bell's conditions and the underlying laws of nature are local realist and respect the no-conspiracy condition, then according to Bell's theorem the
probability this will be violated approaches zero as the number of trials approaches infinity.
rlduncan said:
Again this is Bell's inequality and you are not addressing my point. If a1≠a2 or b1≠b2 or c1≠c2 then a violation will occur.
I don't understand what a1 and a2 are supposed to represent! In
your example where a,b,c represented the result recorded for one of three coins on a glass table (with Bob always recording the opposite of what he sees from under the table), on any trial where Alice and Bob both chose to look at the same coin (say "a"), they're both
guaranteed to get the same result on that trial, no? Give me a
concrete example (like the coin/glass table one) where it's possible that a1≠a2, but I can see clearly what "a1" and "a2" represent, and I can also see that there are a series of trials and on each trial, if Alice and Bob both make the same measurement they are guaranteed to get the same result. If your model doesn't fulfill these conditions, it has
no relevance to Bell's theorem, which is specifically about a scenario where this is the case!
rlduncan said:
Each trial must be indexed
What does "indexed" mean? Each time the two experimenters make observations, they already know what trial number that observation belongs with--there can be no possibility of retroactively changing the numbers assigned to each observation. After all, Bell's theorem is supposed with pairs of entangled particles, we have to make sure that each of Alice's measurement of one member of a pair is assigned the same number as Bob's measurement of the other member of that
same pair, not a member of a different pair.
rlduncan said:
and the sequences checked to see if a1=a2, etc.
Alice and Bob cannot check this, they can only measure a single property on each trial. Yes or no, are you claiming it is possible to have a probability of violating
this inequality that doesn't approach zero as the number of trials goes to infinity, and where the measurements actually fit the experimental conditions Bell was describing? (which would include the fact that Alice and Bob pick in a random or pseudorandom manner what property to measure on each trial, the fact that Alice's cannot causally influence either Bob's choice or the properties associated with the particle/sequence Bob is measuring and vice versa, and the fact that they
always get the same answer on any trial where they both pick the same property to measure)
(Number of trials where object #1 was measured for property A and it
did have A, and object #2 was measured for property B and it
did not have B)
+
(Number of trials where object #1 was measured for property B and it
did have B, and object #2 was measured for property C and it
did not have C)
≥
(Number of trials where object #1 was measured for property A and it
did have A, and object #2 was measured for property C and it
did not have C)
Here the "objects" can be anything you like--particles, triplets of coins as viewed from above or underneath under a glass table, game show contestants being asked one of three questions in separate rooms, whatever. If you think this inequality can be
reliably violated (i.e. the probability of violation doesn't approach zero even in the limit as the number of trials goes to infinity) in a situation that matches the experimental preconditions, then please give me a situation that
clearly respects all those conditions, not just a vague list of symbols with no clear meaning or connection to Bell's experimental preconditions.