- #1
lowerlowerhk
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The first law of thermodynamics
[itex] dU=dQ-dW[/itex]
could be expanded to
[itex] dU=TdS-PdV[/itex]
where
U is internal energy,
T is temperature,
S is entropy,
P is pressure, and
V is volume.
I am trying to understand the terms one by one in plain English.
So:
V is how big the container is,
P is how hard the container is pushing the system,
U is internal energy of system,
T is how willing the system want to give out heat, and
S is how evenly distributed the thermal energy is.
Plus:
[itex]PdV[/itex] is energy (loss) due to the system pushes out the surroundings to make itself a room, and
[itex]TdS[/itex] is energy due to the particles jumping around.
Is there misconception? and
I don't understand why [itex]TdS[/itex] would be a form of energy, why?
[itex] dU=dQ-dW[/itex]
could be expanded to
[itex] dU=TdS-PdV[/itex]
where
U is internal energy,
T is temperature,
S is entropy,
P is pressure, and
V is volume.
I am trying to understand the terms one by one in plain English.
So:
V is how big the container is,
P is how hard the container is pushing the system,
U is internal energy of system,
T is how willing the system want to give out heat, and
S is how evenly distributed the thermal energy is.
Plus:
[itex]PdV[/itex] is energy (loss) due to the system pushes out the surroundings to make itself a room, and
[itex]TdS[/itex] is energy due to the particles jumping around.
Is there misconception? and
I don't understand why [itex]TdS[/itex] would be a form of energy, why?
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