Is There a General Formula for this Partial Fraction Function?

  • Thread starter Thread starter EngWiPy
  • Start date Start date
  • Tags Tags
    Fraction Partial
AI Thread Summary
A general formula for the partial fraction decomposition of the function 1/((ax_1+1)(ax_2+1)...(ax_L+1)) is sought, specifically in the form of c_1/(ax_1+1) + c_2/(ax_2+1) + ... + c_L/(ax_L+1), where c's are constants. The discussion clarifies that 'a' is treated as the variable while the 'x's are constants, meaning the c's are determined by the values of the x's. The complexity increases with larger values of L, but a general solution expression has been found. The conversation emphasizes understanding the relationship between the variables and constants in partial fraction problems.
EngWiPy
Messages
1,361
Reaction score
61
Hello,

Is there any general formula for the partial fraction of the following function:

\frac{1}{(ax_1+1)(ax_2+1)\cdots (ax_L+1)}

I can work for L=3, but it get involved for larger L!

Thanks in advance
 
Mathematics news on Phys.org
Ok... from what I've understood, you want write

\frac{1}{(ax_1+1)(ax_2+1)\cdots(ax_L+1)}

as

\frac{c_1}{ax_1+1}+\frac{c_2}{ax_2+1}+\cdots+\frac{c_L}{ax_L+1}

where the c's are constants. My question is, what is the variable the c's must be independent of? a or x?
 
coelho said:
Ok... from what I've understood, you want write

\frac{1}{(ax_1+1)(ax_2+1)\cdots(ax_L+1)}

as

\frac{c_1}{ax_1+1}+\frac{c_2}{ax_2+1}+\cdots+\frac{c_L}{ax_L+1}

where the c's are constants. My question is, what is the variable the c's must be independent of? a or x?

a is a constant, and x's are the variables.
 
coelho said:
Ok... from what I've understood, you want write

\frac{1}{(ax_1+1)(ax_2+1)\cdots(ax_L+1)}

as

\frac{c_1}{ax_1+1}+\frac{c_2}{ax_2+1}+\cdots+\frac{c_L}{ax_L+1}

where the c's are constants. My question is, what is the variable the c's must be independent of? a or x?

Problems involving partial fractions usually have one variable and many constants. From the appearance of your expression, I assume a is the variable and the x's are constants. In that case the c's will be determined by the x's.
 
mathman said:
Problems involving partial fractions usually have one variable and many constants. From the appearance of your expression, I assume a is the variable and the x's are constants. In that case the c's will be determined by the x's.

yes, right. a is the variable and x's are the constants. I got the general solution expression.

Thanks
 
Thread 'Video on imaginary numbers and some queries'
Hi, I was watching the following video. I found some points confusing. Could you please help me to understand the gaps? Thanks, in advance! Question 1: Around 4:22, the video says the following. So for those mathematicians, negative numbers didn't exist. You could subtract, that is find the difference between two positive quantities, but you couldn't have a negative answer or negative coefficients. Mathematicians were so averse to negative numbers that there was no single quadratic...
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. In Dirac’s Principles of Quantum Mechanics published in 1930 he introduced a “convenient notation” he referred to as a “delta function” which he treated as a continuum analog to the discrete Kronecker delta. The Kronecker delta is simply the indexed components of the identity operator in matrix algebra Source: https://www.physicsforums.com/insights/what-exactly-is-diracs-delta-function/ by...
Thread 'Unit Circle Double Angle Derivations'
Here I made a terrible mistake of assuming this to be an equilateral triangle and set 2sinx=1 => x=pi/6. Although this did derive the double angle formulas it also led into a terrible mess trying to find all the combinations of sides. I must have been tired and just assumed 6x=180 and 2sinx=1. By that time, I was so mindset that I nearly scolded a person for even saying 90-x. I wonder if this is a case of biased observation that seeks to dis credit me like Jesus of Nazareth since in reality...

Similar threads

Back
Top