Calculating Expected Value for Sweepstakes Prizes

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To calculate the expected value for sweepstakes prizes, the probabilities of winning each prize must be established alongside their respective values. The expected value formula is E[X] = Σ(X_i * P(X_i)), where X_i represents the prize amounts and P(X_i) their probabilities. The discussion highlights the need to factor in the entry cost of 75 cents when determining the overall expected value. The correct probabilities for each prize are derived from the odds provided, such as 1/8100 for the $5900 prize. Ultimately, the expected value calculation leads to a result of $0.62 per entry after accounting for the entry fee.
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The prizes that can be won in a sweepstakes are listed below together with the chances of winning each one.

$5900(1 chance in 8100); $2500( 1 chance in 6200); $600 (1 chance in 4700); $300(1 chance in 2600)
Find the expected value of the amount won for one entry if the cost to enter is
75 cents.

Now I am having trouble setting this up as a probability distribution. I just don't know where to start or what goes where. I know the awnser is $0.62..but i just can't figure out the steps. So far i'v been doing it like this

x P(x)
----- ------
Win $5899.25 ?
Lose -$.75 ?

Well I think I'm setting up "x" wrong and I just don't know what the probability should be. So any help would be apreciated.
 
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For example, 1 chance in 100 is a probability.
So you have the probability of every winning and the amount of each winning. Now, the expected value is

E\left[ X \right] = \sum\limits_{i = 1}^n {X_i P\left( {X_i } \right)}

X_i is the amount of each winning and P\left( {X_i } \right) is the probability of each winning.
And don't forget to take into account the 75 cents the entry consts.
 
"One chance in 8100" means the probability is 1/8100, "one change in 6200" mean the probability is 1/6200, etc.
 
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