Electric Field Projectile Motion

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SUMMARY

The discussion focuses on determining the exit angle of electrons from a uniform electric field between parallel plates, specifically with a length of 5.4 cm and an electric field strength of E = 5.0 x 10^3 N/C. The horizontal position of the electrons is described by the equation x = V0*t, while the vertical position is given by y = -((e*E)/(2*m*V0^2))(x^2). The angle of exit is directly related to the slope of the tangent to the electron's trajectory at the exit point, with the velocity parallel to the plates remaining constant and the perpendicular velocity calculated using energy conservation principles.

PREREQUISITES
  • Understanding of electric fields and forces on charged particles
  • Familiarity with kinematic equations in projectile motion
  • Knowledge of energy conservation principles in physics
  • Basic understanding of the properties of electrons, including charge and mass
NEXT STEPS
  • Explore the derivation of projectile motion equations in electric fields
  • Study the effects of varying electric field strengths on electron trajectories
  • Learn about the implications of fringing fields in practical applications
  • Investigate the role of initial velocity (V0) in determining exit angles
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Physics students, educators, and professionals in fields related to electromagnetism and particle motion, particularly those studying the behavior of charged particles in electric fields.

physicsss
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At what angle will the electrons leave the uniform electric field at the end of the parallel plates? Assume the plates are 5.4 cm long and E = 5.0 x 10^3 N/C. Ignore fringing of the field. (counterclockwise from the x-axis is positive)

I know the horizontal position is given by x=V0*t and
y= -((e*E)/(2*m*V0^2))(x^2) where e is charge of the electron and x is the horizontal position...
 

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physicsss said:
At what angle will the electrons leave
..relates to the slope of the tangent to their trajectory. [That was a hint.]
 
1. Direction in which it leaves is same as that of velocity at the point.

2. Velocity parallel to the plates will remain same.

3. Velocity perpendicular to the plates can be calculated using force of energy conservation.
 

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