Q is a conserved charge if \{Q, H\} = 0
Show that q+\epsilon\delta q satisfies the equation of motion.
\delta q = \{q, Q\}
I couldn't find the proof. Anybody knows?
My workings:
\delta q = \{q, Q\}
\delta\dot{q} = \{\{q,Q\},H\} = - \{\{Q,H\},q\} - \{\{H,q\},Q\}
\delta\dot{q} = \{\{q,Q\},H\} =...