Taylor Definition and 849 Threads
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Starting a Taylor series problem, .
Compute the Taylor series for f(x)= sq root (x) about x=1. Determine where the series sconverges absolutely, converges conditionally, and diverges. Hint: 2(k!)=2*4*6...(2k-2)*2k. Also 1<2, 3<4, 5<6,..., 2k-1<2k should help you out with a comparision.- ArcainineFalls531
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- Series Taylor Taylor series
- Replies: 1
- Forum: Calculus and Beyond Homework Help
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Is This the Correct Taylor Polynomial for sqrt(x) at x=100?
Hi Given a function f(x) = sqrt(x) is the Taylor Polynomial of degree 2 for that function: \frac{x^2}{2} - 99x + 4901 where x = 100 ? Sincerely Fred- Mathman23
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- Polynomials Taylor
- Replies: 2
- Forum: Calculus and Beyond Homework Help
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Complex analysis taylor series Q
hi, I'm wondering if someone can help me out with this question: "What are the first two non-zero terms of the Taylor series f(z) = \frac {sin(z)} {1 - z^4} expanded about z = 0. (Don't use any differentiation. Just cross multiply and do mental arithmetic)" I know the formula for...- ElDavidas
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- Analysis Complex Complex analysis Series Taylor Taylor series
- Replies: 1
- Forum: Calculus and Beyond Homework Help
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Complex Variable Taylor Expansion at z=2i
I'm having trouble determining the order of the pole of [exp(iz) - 1]/((z^2) + 4) at z=2i I know I can't just expand the exponential as 1 + iz + [(iz)^2]/2 ... because this formula only works near the origin. Can I still use Taylor's theorem to find the expansion at z=2i (i.e does...- sachi
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- Complex Expansion Taylor Taylor expansion Variable
- Replies: 1
- Forum: Calculus and Beyond Homework Help
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What is the Taylor expansion for ln(1+z)?
the problem reads develop expansion of ln(1+z) of course I just tried throwing it into the formula for taylor expansions, however I do not know what F(a) is, the problem doesn't specify, so how can I use a taylor series?- Wishbone
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- Expansion Taylor Taylor expansion
- Replies: 40
- Forum: Calculus and Beyond Homework Help
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Taylor Series for ln(1-x): Get Help Now
may i know from ln(1-x) how to become - [infinity (sum) k=1] x^k / k ? pls help- teng125
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- Ln Series Taylor Taylor series
- Replies: 3
- Forum: Precalculus Mathematics Homework Help
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Spacetime Physics by J. Wheeler and E. Taylor
I have had this book for a while and never really looked into it. It claims to be an easy/nonmathematical approach to relativity. Has anyone read this book before? Can I really understand what the subject matter is covering without any post-calculus math? Is it also a good beginer's guide to...- Plastic Photon
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- Physics Spacetime Taylor Wheeler
- Replies: 9
- Forum: Science and Math Textbooks
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Taylor series homework problem
Dear friends, I have a question on a taylor series, that is this one: A·e^(i (x)) That is: cos (x)+ i sin (x) becouse of the taylor's. But, is this wrong? A·e^(v (x)) = cos (x)+ v sin (x) (v is a vector). Tks.- Plat00n
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- Homework Homework problem Series Taylor Taylor series
- Replies: 3
- Forum: Calculus and Beyond Homework Help
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Calculating Limits with Taylor Series: Tips and Guidelines for Accurate Results
Taylor rule of thumb?? When calculating limits by using taylor series is there any easy way to know how many elements that should be included in the taylor series? if I have \lim_{x\rightarrow\zero} \frac{exp(x-x^2)-Cos2x-Ln(1+x+2x^2)}{x^3} How do I know many terms to include in...- Azael
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- Taylor
- Replies: 7
- Forum: Calculus and Beyond Homework Help
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Taylor Expansion Hints: Find First Non-Zero Term of x = 0
Can anyone please give me a hint on any of the following Taylor expansions? That would be so helpful! for all three: Find the first non-zero term in the Taylor series about x = 0 problem 1 \frac{1} {sin^2x} - \frac{1} {x^2} everytime I differentiate the result is zero...so that...- *Alice*
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- Expansion Taylor Taylor expansion Term
- Replies: 7
- Forum: Calculus and Beyond Homework Help
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Taylor Series to x places of decimals
Hi all, here's the problem: [FONT="Arial"][FONT="Century Gothic"]given: tan^(-1)= x - x^3/3 + x^5/5 using the result tan^(-1) (1)= pi/4 how many terms of the series are needed to calculate pi to ten places of decimals? note: this is supposed to say tan^(-1) and tan^(-1)[1]...- *Alice*
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- Series Taylor Taylor series
- Replies: 6
- Forum: Calculus and Beyond Homework Help
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What did I do wrong in my Taylor Series Expansion for y=kcosh(x/k)?
y=kcosh(x/k) = k(e^(x/w) + e^(-x/k)) y ~ k[1 + x/k + (1/2!)(x^2/k^2) + (1/3!)(x^3/k^3)] +...+ k[1 - x/k +(1/2!)(x^2/k^2) - (1/3!)(x^3/k^3) +...] All odd terms except 1 cancel out. So we are left with y = k [2 + (2/2!)(x^2/k^2) + (2/4!)(x^4/k^4) + (2/6!)(x^6/k^6) +...] I've been...- Nusc
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- Expansion Series Series expansion Taylor Taylor series
- Replies: 2
- Forum: Calculus and Beyond Homework Help
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Studying Taylor and Maclaurin Series
So I'm studying Taylor Series (I work ahead of my calc class so that when we cover topics I already know them and they are easier to study..) and tonight I found a formula for taylor series and maclaurin series, and i used them to prove eulers identity. However, I don't really know much about... -
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Can the Taylor series be inverted without using Lagrange's theorem?
How can you invert a Taylor serie? x=y+Ay^2+By^3+Cy^4... to y=ax+bx^2+cx^3 ... without the lagrange theorem... must go from x=y+Ay^2+By^3+Cy^4... to y=ax+bx^2+cx^3 ... Need help thanks! -
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How Can You Derive the Taylor Series of 1/sqrt(cosx) Using the Series for cosx?
Is there a way to get the Taylor series of 1/sqrt(cosx), without using the direct f(x)=f(0)+xf'(0)+(x^2/2!)f''(0)+(x^3/3!)f'''(0)... form, just by manipulating it if you already know the series for cosx?- ascky
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- Series Taylor Taylor series
- Replies: 1
- Forum: Calculus and Beyond Homework Help
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Taylor Polynomial (n=4) for g(x): Showing 0<E4(x)<80x^5
Hi I have found the following TP (n=4) for g(x) = (1+5x)^1/5 P4(x) = 1+x-2x^2+6x^3-21x^4 Then they ask me to show that 0<E4(x)<80x^5 when x>0. I don't know how to start, or exactly what I am supposed to show...? I have found E4(x) to be( 399/[5(1+5X)^24/5] ) *x^5... And 0<X<x ...?- sony
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- Polynomial Taylor
- Replies: 2
- Forum: Introductory Physics Homework Help
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Solving Differential Equations with Simple Taylor Series Method
Hi, I was reading this math book once... and it had a method for solving differential equations of 1st (And maybe 2nd? I don't remember) order by using simple Taylor series... I didn't even have to understand much of what was going on, except that I followed some simple rule and I ended up...- Pseudo Statistic
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- Series Taylor Taylor series
- Replies: 4
- Forum: Differential Equations
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Taylor Polynomial for f(x) = √(x+1) | Approximate & Find Error
Find the thrid taylor polynomial P3(x) for the function f(x) = \sqrt{x+1} about a=0. Approximate f(0.5) using P3(x) and find actual error thus Maclaurin series f(x) = f(0) + f'(0)x + \frac{f''(0)}{2} x^2 + \frac{f^{3}(0)}{6} x^3 f(x) = x + \frac{1}{2} x - \frac{1}{8} x^2 +...- stunner5000pt
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- Polynomial Taylor
- Replies: 3
- Forum: Introductory Physics Homework Help
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Approximate the integral int (1 - cos x)/x dx using Taylor expansion
I am supposed to find an approximation of this integral evaluated between the limits 0 and 1 using a taylor expansion for cos x: \int \frac{1 - cos x}{x}dx and given cos x = 1 - \frac{x^2}{2!} + \frac{x^4}{4!} - \frac{x^6}{6!}... i should get a simple series similar to this for...- thenewbosco
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- Approximate Cos Dx Expansion Integral Taylor Taylor expansion
- Replies: 1
- Forum: Introductory Physics Homework Help
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Understanding Taylor Series Error & Degrees of Variables
Hi, can someone explain me the relation between the degree of a taylor series (TS) and the error. It is for my class of numerical method, and I do not find a response to my question in my textbook. I mean when we have a function Q with two variables x and y,and we use a version of TS to... -
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How Does the Degree of a Taylor Series Affect Error in Numerical Methods?
Hi, can someone explain me the relation between the degree of a taylor series (TS) and the error. It is for my class of numerical method, and I do not find a response to my question in my textbook. I mean when we have a function Q with two variables x and y,and we use a version of TS to... -
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Solving Taylor Series Problem with m-th Derivative Bound
Hi , I have some difficulties to solve this problem. It is from my numerical methods class but the problem is about taylor series: It is known that for 4 < x < 6, the absolute value of the m-th derivative of a certain function f(x) is bounded by m times the absolute value of the quadratic...- brad sue
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- Bound Derivative Series Taylor Taylor series
- Replies: 2
- Forum: Introductory Physics Homework Help
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What is the proof of the Taylor Theorem in n variables?
Hello, guys. I am studying the Taylor Theorem for functions of n variables and in one book I've found a proof based on the lemma that I am copying here. I am having some trouble in following its proof so I seek your kind assistance. The lemma rests on two items: the definition of a function... -
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What is the Taylor expansion for 1/(1-exp(-1))?
Hi How do you expand (1-exp(-1))^-1 as Taylor series Callisto- Callisto
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- Expansion Taylor Taylor expansion
- Replies: 7
- Forum: Introductory Physics Homework Help
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Taylor differentition polynomials?
taylor differentition polynomials? hi got a question here that involves this extremely difficult question anyone that can point me in the right direction on what to do will be most appreciated :) Find Exactly the tayor polynomial of degree 4 f(x) = cos ( pi*x / 6 ) about x=-1 i know...- dagg3r
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- Polynomials Taylor
- Replies: 8
- Forum: Introductory Physics Homework Help
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Taylor series expansion question
Hi, I have a question about Taylor series: I know that for a function f(x), you can expand it about a point x=a, which is given by: f(x) = f(a) + f'(a)(x - a) + \frac{f''(a)}{2!}(x - a)^2 + ... but I would like to do it for f(x+a) instead of f(x), and expand it about the very same point...- meteorologist1
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- Expansion Series Series expansion Taylor Taylor series
- Replies: 2
- Forum: Calculus
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Taylor Series Expansion for z^i at z=1+i: First Three Terms
I need to find the first three terms of this series. Am I correct in saying z^i = exp(i*Log(z)), then using the taylor series for e^z, giving me: (i*Log(z)) - 1/2*(Log(z))^2 - i/6*(Log(z))^3 + 1/24*(Log(z))^4 + ... I haven't worked it out, but this seems to mean that the coefficients... -
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Taylor Series for Showing B_{x}(x+dx)-B_{x}(x) Approximation
How do i show that B_{x}(x+dx,y,z)-B_{x}(x,y,z)\approx \frac{\partial B_{x}(x,y,z)}{\partial x} dx using a Taylor series to the first term. Using a Taylor series does B(x) = B(a) + B'(a)(x-a)? In that case what would B(x+dx) be and how can i obtain the desired result from this? Thanks in...- retupmoc
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- Approximation Series Taylor Taylor series
- Replies: 3
- Forum: Introductory Physics Homework Help
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Finding Taylor Series of Functions - Tips to Make it Easier
I was wondering if someone can give me some tips for finding the taylor series of functions. For example this was a test question we had: Find the taylor series of f(x)=ln(x) about x=e I know how to start it off but I get confused halfway through and can't seem to figure out what to do...- pnazari
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- Functions Series Taylor Taylor series Tips
- Replies: 3
- Forum: Introductory Physics Homework Help
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How Is the Full Taylor Series Derived Beyond Its Linear Approximation?
I understand what a linear approximation, and how it is derived using the point-slope formula: f(x)\approx f(a)+f'(a)(x-a) These are the first three terms of a Taylor series, so I was wondering how the rest was derived? Thanks for your help. -
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Taylor Approximation Help - Find n Given x, a, ErrorBound
Hi, I'm having trouble doing my work where I have to find the Taylor Approximation of function. My real work is the program this thing when the function, x, a, and ErrorBound is given. I don't knwo what to do with the ErrorBound to get n, where n is the number of terms. do i make any sense...- scan
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- Approximation Taylor Taylor approximation
- Replies: 2
- Forum: Introductory Physics Homework Help
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Taylor Polynomial of 6th Degree for ln(1-x^2) with c=0
I just want to check my answer. The question asks for the Taylor polynomial of degree 6 for ln(1-x^2) for -1<x<1 with c=0. I got tired after differentiating 6 times so I'm worried I made some mistakes along the way. The question also said: hint: evaluate the derivatives using the formula...- shan
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- Polynomials Taylor
- Replies: 4
- Forum: Introductory Physics Homework Help
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Proving Pn(x^2) as the 4n+2-nd Taylor Polynomial of sin(x^2) using Rn(x) Limits
Show that Pn(x^2) is the 4n+2-nd Taylor polynomial of sin(x^2) by showing that \lim_{n\rightarrow infinity} R2n+1(x^2) = 0. note that Rn(x) represents the remainder I'm stuck on this question, can anyone help me please? -
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Taylor series exp. & a couple of other questions
Problem Find the sum of the series s(x) = \sum _{n=1} ^{\infty} \frac{1}{2^{n}} \tan \frac{x}{2^n} Solution If s(x) = \sum _{n=1} ^{\infty} \frac{1}{2^{n}} \tan \frac{x}{2^n} = \frac{x}{3} + \frac{x^3}{45} + \frac{2x^5}{945} + \dotsb \cot x = \frac{1}{x} - \frac{x}{3} -...- DivGradCurl
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- Couple Series Taylor Taylor series
- Replies: 1
- Forum: Introductory Physics Homework Help
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Taylor Expansion for Large R: Showing V Approximates $\frac{\pi a^2 \sigma}{R}$
V = 2\pi \sigma(\sqrt{R^2+a^2}-R) Show that for large R, V \approx \frac{\pi a^2 \sigma}{R} I figured if I could develop the MacLaurin serie with respect to an expression in R such that when R is very large, this expression is near zero, then the first 1 or 2 terms should be a fairly...- quasar987
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- Expansion Taylor Taylor expansion
- Replies: 6
- Forum: Introductory Physics Homework Help
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Can someone help me understand Taylor and MacLaurin series?
I am having difficulty understanding Taylor and MacLaurin series. I need someone to go through step by step and explain a problem from beginning to end. You could use the function f(x) = cos x. Also, could someone find the MacLaurin series of 1/(x^2 + 4) ? I just don't understand the basics of...- Wee Sleeket
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- Maclaurin Maclaurin series Series Taylor
- Replies: 4
- Forum: Calculus
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Finding Taylor Polynomial for f(x) = (1+x)^{2/3}
1. Let f(x) = (1+x)^{2/3} (a) find the taylor polynomial T_2(x) of f expanded about a = 0. i got 1 + (1/3)x - (1/9)x^{2} For the rest, i have no idea how to do...any help would be greatly appreciated. (b) For the givven f write the lagrange remainder formula for the error term...- 3.14159265358979
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- Polynomial Taylor
- Replies: 4
- Forum: Calculus
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Mathematica Obtain 8th Degree Taylor Polynomial for Sqrt(x) with Mathematica
In order to obtain with the aid of Mathematica, say, an 8-th degree Taylor polynomial of \sqrt{x} centered at 4 , I use the following command: Normal[Series[Sqrt[x], {x, 4, 8}]] and I get \sqrt{x} \approx 2 + \frac{1}{2^2} \left( x - 4 \right) - \frac{1}{2^6} \left( x - 4 \right) ^2...- DivGradCurl
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- Taylor
- Replies: 7
- Forum: MATLAB, Maple, Mathematica, LaTeX
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Taylor Series/Radius of Convergence - I just need a hint
Consider the following: f(x) = 1 + x + x^2 = 7 + 5 (x-2) + (x-2)^2 which is a Taylor series centered at 2. My question is: what is the radius of convergence? The answer in my book is R=\infty , but take a look at this: f(x) = 7 + 5 (x-2) + (x-2)^2 = \sum _{n=0} ^{\infty} b_n (x-2)^n...- DivGradCurl
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- Convergence Taylor
- Replies: 3
- Forum: Introductory Physics Homework Help
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Confused about taylor approximation
I am a bit confused about taylor approximation. Taylor around x_0 yields f(x) = f(x_0) + f'(x_0)(x-x_0) + O(x^2) which is the tangent of f in x_0, where f'(x) = f'(x_0) + f''(x_0)(x-x_0) + O(x^2) which adds up to f(x) &=& f(x_0) + (f'(x_0) + f''(x_0)(x-x_0) +...- LostInSpace
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- Approximation Confused Taylor Taylor approximation
- Replies: 2
- Forum: Calculus
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What's the purpose of Taylor Polynomials?
I don't get it. I use it to approximate f for some x, but the formula for Taylor Polynomials already has f in it? -
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Taylor Series Problem Solved: Coefficient of x^7
Help me out with this Taylor series problem: The Taylor series for sin x about x = 0 is x-x^3/3!+x^5/5!-... If f is a function such that f '(x)=sin(x^2), then the coefficient of x^7 in the Taylor series for f(x) about x=0 is? thanks- dbzgtjh
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- Series Taylor Taylor series
- Replies: 3
- Forum: Differential Equations
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Dummy Variables in Taylor Series
Taylor Series in x-a Hi, I've got a question about the use of dummy variables in Taylor Series. We are asked to expand: g(x) = xlnx In terms of (x-2). So originally, I used a dummy variable approach to try and find an answer. Let t = x-2, so x = t+2. g(x) = (t+2)ln(2+t)...- AngelofMusic
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- Series Taylor Taylor series Variables
- Replies: 2
- Forum: Introductory Physics Homework Help
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Taylor Series Solution for y'' = e^y at x=0, y(0)=0, y'(0)=-1
This problem has been bugging me and I can't seem to figure it out: y'' = e^y where y(0)= 0 and y'(0)= -1 I'm supposed to get the first 6 nonzero terms I know the form is: y(x) = y(0) + y'(0)x/1! + y''(0)x^2/2! + y'''(0)x^3/3! +... and I know the first two terms are y(x) = 0 -...- dduardo
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- Series Taylor Taylor series
- Replies: 2
- Forum: Differential Equations
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Taylor Polynomials: Approximating f(x) and f'(x)
Let f be a function that has derivatives of all orders for all real numbers. Assume f(1)=3, f'(1)=-2, f"(1)=2, and f'''(1)=4 a. Write the second-degree Taylor polynomial for f about x=1 and use it to approximate f(0.7). b. Write the third-degree Taylor polynomial for f about x=1 and use it... -
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Taylor Series for ln(x+1) at x=1
Find the 4th term of the Taylor series centerd at x=1 for f(x)=ln(x+1) f(x)=ln(1=x) f'(x)=(1+x)^-1 f"(x)=(-1)[(1+x)^-2] f"'(x)=(2)[(1+x)^-3] f""(x)=-6[(1+x)^-4)] Plug in 1: .6931 .5 -.25 .25 -.375 What do I do next? (Also, is the 4th term the 4th term starting with f(x)? or the... -
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Taylor series with partial derivatives
We were gievn a question in tutorial last week asking us to calculate the Taylor series of the function f(x,y) = e^(x^(2) + y^(2)) to second order in h and k about the point x=0, y=0 I've got the forumla here with all the h's and k's in it and have it written down, but it's actually how to... -
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How does Taylor series help expand the function 1/sqrt(1-x^2)?
basic taylor expansion... Hi, could some one explain how i could use the taylor series to expand out: f(x)= 1/sqrt(1-x^2) Any help would be appreciated, thanks.- robgb
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- Expansion Taylor Taylor expansion
- Replies: 7
- Forum: General Math
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What is the Taylor series for i^i?
I'm having some problems expanding i^i, could anyone help? I know it becomes a real number somehow, and I'm familiar with the e^(i * pi) expansion, but is the i^i done in the same way?- Khan
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- Series Taylor Taylor series
- Replies: 2
- Forum: Introductory Physics Homework Help