Complex analysis taylor series Q

Click For Summary
SUMMARY

The discussion focuses on finding the first two non-zero terms of the Taylor series for the function f(z) = sin(z) / (1 - z^4) expanded about z = 0. Participants emphasize using the Taylor series for sin(z) and the geometric series for 1/(1 - z^4) without differentiation. The key takeaway is that by expanding both series and multiplying them, one can derive the required terms through mental arithmetic and cross-multiplication.

PREREQUISITES
  • Understanding of Taylor series expansion
  • Familiarity with the Taylor series for sin(z)
  • Knowledge of geometric series for 1/(1 - z^4)
  • Ability to perform algebraic manipulation and mental arithmetic
NEXT STEPS
  • Study the Taylor series expansion of sin(z)
  • Learn about geometric series and their applications
  • Practice multiplying series to find products of functions
  • Explore advanced techniques in series convergence and manipulation
USEFUL FOR

Students and educators in mathematics, particularly those studying calculus and series expansions, as well as anyone interested in applying Taylor series to complex functions.

ElDavidas
Messages
78
Reaction score
0
hi, I'm wondering if someone can help me out with this question:

"What are the first two non-zero terms of the Taylor series

[tex]f(z) = \frac {sin(z)} {1 - z^4}[/tex] expanded about z = 0.

(Don't use any differentiation. Just cross multiply and do mental arithmetic)"

I know the formula for a Taylor series but I can't see how to do this with just cross multiplying and mental arithmetic.

Thanks
 
Physics news on Phys.org
This is a product of two functions: sin(z) and 1/(1-z^4).
If you know the Taylor series of both, you can find their product by 'expanding the brackets'
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
Replies
4
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 17 ·
Replies
17
Views
4K
Replies
6
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
5
Views
2K
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K