From ##\vec r''(t)## we integrate to get
$$\vec r'(t) = \left(-\sin(t)+C_1\right)\hat i + \left(6\cos(2t)+C_2\right)\hat j - \left(9.8t+C_3\right)\hat k$$
Solving for the C constants using ##\vec r'(0) = 1\hat i + 6\hat j + 0\hat k##,
##\vec r'(0) = <C_1, C_2, C_3>##
##=<1, 6, 0>##
So we now...