(1.0 / 2) process repeated 5 times; what is the algrabraic formula?

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1 / 2 = 0.5
0.5 / 2 = 0.25
0.25 / 2 = 0.125
0.125 / 2 = 0.0625
0.0625 / 2 = 0.03125

What is the algebraic formula for this?
 
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\frac{1}{2^5}
 
This is a new one;

64 / 2 = 32
32 / 2 = 16
16 / 2 = 8
8 / 2 = 4
4 / 2 = 2
2 / 2 = 1
1 / 2 = 0.5
0.5 / 2 = 0.25
0.25 / 2 = 0.125
0.125 / 2 = 0.0625
0.0625 / 2 = 0.03125

\frac{64}{2^{10}}
 
Last edited:
Thanks.
 
That should actually be \frac{64}{2^{11}}.

Edit: Enclose your "10" in { } to make it appear correctly.
 
Your right, I added one too many and thought there was only ten.
 
Thanks for the editing tip.
 
jgens said:
\frac{1}{2^5}

But that's not a formula.

\frac{1}{2^n} is a formula.
 
Char. Limit said:
But that's not a formula.

I could nitpick and argue that \frac{1}{2^n} is actually an expression and not a formula since it does not contain an equals sign; but the distinction is really not all that relevant. The OP wanted to know how to express "1 divided by 2 fives times" algebraically and one way is \frac{1}{2^5}. I really don't understand the objection.
 
  • #10
mr magoo said:
This is a new one;

64 / 2 = 32
32 / 2 = 16
16 / 2 = 8
8 / 2 = 4
4 / 2 = 2
2 / 2 = 1
1 / 2 = 0.5
0.5 / 2 = 0.25
0.25 / 2 = 0.125
0.125 / 2 = 0.0625
0.0625 / 2 = 0.03125

\frac{64}{2^{10}}

Also notice that since we divided 64 by 2 five times and we got to 1, so \frac{64}{2^5}=1 rearranging, we get 64=2^5 so we can express the answer as

\frac{64}{2^{10}}=\frac{2^5}{2^{10}}

And if you remember the rule of indices, \frac{2^a}{2^b}=2^{a-b} so \frac{2^5}{2^{10}}=2^{5-10}=2^{-5}=\frac{1}{2^5}

As we got in your first question.
 
  • #11
The formula (not sure if this is considered algebraic) or notation for a product series in the original example would be:

\prod_{i=1}^5 \ \frac{1}{2}
 
Last edited:

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