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gracy
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Have I labeled correctly?
Almost. u and v are correct, but not f. f is the focal length of the lens, not the distance from lens to image. (That's what v is.) Look it up!gracy said:Have I labeled correctly?
I got you point.I think the image below greatly explains all the three f,v,u.Doc Al said:f is the focal length of the lens, not the distance from lens to image. (That's what v is.)
Doc Al said:Almost u and v are correct
The equation 1/f=1/u+1/v is known as the thin lens equation. It relates the focal length (f) of a lens to the object distance (u) and image distance (v) from the lens. It is used to calculate the position and size of an image formed by a lens.
To solve for f, u, and v in the equation 1/f=1/u+1/v, you can use algebraic manipulation. Rearrange the equation to solve for the unknown variable. For example, to find f, you would multiply both sides by (uv) to get f = uv/(u+v).
The equation 1/f=1/u+1/v is an important equation in optics as it helps in understanding the behavior of light when passing through a lens. It is used to calculate the focal length of a lens and to predict the position and size of an image formed by the lens.
Yes, the 1/f=1/u+1/v equation can be applied to all types of lenses, including convex, concave, and combination lenses. This equation is based on the thin lens approximation, which is applicable to all types of lenses as long as the thickness of the lens is small compared to the radii of curvature of its surfaces.
The 1/f=1/u+1/v equation is directly related to the formation of images by lenses. It helps to determine the position and size of an image formed by a lens. The focal length of a lens plays a crucial role in determining the magnification and location of the image formed by the lens. This equation also shows the inverse relationship between the object distance (u) and image distance (v) from the lens, which means that as one increases, the other decreases.