10^(1/10) is VERY close to 2^(1/3)

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The discussion centers on the numerical approximation of \(10^{1/10}\) and \(2^{1/3}\), which are approximately 1.2599 and 1.2589, respectively. Participants explore whether the closeness of these values is coincidental or has a deeper mathematical significance. The consensus is that while the two values are indeed close, they are not sufficiently accurate to be interchangeable without consideration of precision. The source of this inquiry is linked to an engineering document discussing vibration testing of small satellites.

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Is there a subjacent reason that explains why these two numbers are so close?
$$10^{1/10} \approx 2^{1/3}$$

For context, this is where I found out about this.
Source: https://www.instarengineering.com/p...ration_Testing_of_Small_Satellites_Part_5.pdf
1708777676533.png


Is it just a coincidence? I tried factoring the numbers but it doesn't provide any additional information. From the infinite number of possibilities, how did they realize that ##10^{1/10} \approx 2^{1/3}## are so close together that it is acceptable to use the ##2^{1/3}## without losing too much accuracy?
 
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##2^{10}=1024, \sqrt[3] {1024} \approx 10##
 
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How did I not see it? 🤦‍♂️
Thank you. It's clear now.
 
Juanda said:
Is it just a coincidence?
Pretty much -- ##10^{1/10}## is not all that close to ##2^{1/3}##.
The first is ~1.2599, and the second is ~1.2589. Rounding to 3 decimal places gives 1.260 vs. 1.259. I guess these are close if you consider ##\sqrt 2 \approx 1.4## as they did in the quoted article.
 

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