# 10 Calculus Questions Integrals,Equations, PDF file, Dead line after 1 hour

1:
a- x= 1/10 (9-√41) ≈0.259688,Or x=1/10 (9+√41)≈1.54031
b:y=0 Or y=7/3
c: didn't solve.
d: t= 1/3 log⁡(5/2)≈0.30543
e::β=3/5 Or β=-3/5

2: didn't solve.

3:sin^-1⁡(√5/4)≈0.59
tan (0.59)≈0.67

4: didn't solve

5:sin⁡(α)+cos⁡(α)=4/3
We solve the equation
α= 2tan^-1⁡(1/7 (3-√2))〗
We calculate sin⁡(2α)
sin⁡(2α)=7/9

6:max⁡{f(x)=x^3-5x^2-8x+12}=400/27 at x=-2/3

7:
a: 0
didn't solve b,c,d,e

8: The angle is 109.5 degrees

9:
a :: e^2x (6x^2+6x-sin⁡(x)+2 cos⁡(x)+10)
b: 6y log⁡(5)
c: sec⁡θ
d: 800
e: z( log⁡(z)-1)+constant

10 : didn't solve.

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If i want to type the work i did it would take about 2 hours i'm sorry i'm slow at typing and now time is against me , i started since 3 hours.

If you don't type out the work you did, then I'm afraid nobody here is going to help you.

jedishrfu
Mentor
why not take a picture of your handwritten work or scan it and post that just like you did with the pdf?

Guys please help me right now and after sending my answers to my teacher i'll tell you my work on each of the problems

i don't have a scanner the pdf was sent by the teacher

and the teacher said you can seek help with other people

because the questions are hard

Guys please help me right now and after sending my answers to my teacher i'll tell you my work on each of the problems
Nope, that isn't possible. PF isn't a place where you go, ask a question and immediately get an answer.

Nope, that isn't possible. PF isn't a place where you go, ask a question and immediately get an answer.
Well, you will get immediately an answer if you show some work Seriously though, you received this assignment a week ago and you're asking for help an hour before the deadline?? That's poor planning from your side. Next time, you should ask for help earlier.

LCKurtz
Homework Helper
Gold Member
Since you are pressed for time, I will save you a little time by quoting from the FAQ thread, which is first top thread in this group.

Quote:

"Did you post that your homework is due in a few hours and that you need help NOW?
If you did, then you should remove this. It doesn't get you a faster response. Some people even refuse to help posters who post things like "ASAP", "Help needed fast", etc.
Also, if your homework is due in a few hours, then perhaps you should have asked help on it earlier. People here are volunteers and are not paid to help you. We will answer when we can, but it's not nice to put us under pressure."

the date was when the pdf was created not received by me, i received this pdf today before 4 hours

if i knew how to solve them i wouldn't have asked :(

PS: our teacher gave his this homework without teaching us about functions and derivatives

i tried solving them before posting on the fourms

YES : I just talked to the teacher the deadline was change to next Wednesday instead of today :)

Last edited:
Deadline was changed now i have a whole week to solve the problems :)

Deadline was changed now i have a whole week to solve the problems :)
Good, then which question would you like to start with? It would have been better if you made a seperate thread for each question.

Mark44
Mentor
Good, then which question would you like to start with? It would have been better if you made a seperate thread for each question.
Yes, I agree. You (Phys student) will likely get more helpful responses by showing a single problem with your work than by throwing up a whole laundry list of problems.

(e) if m1=m2=m3

i'll convert everything to m1

a= g(3m1m1-4m1m1-m1m1)/(m1m1+m1(4m1+m1)

simplifying (3m1^2 -4m1^2-m1^2)/(m1^2+4m1^2+m1^2)
(-2m1^2)/(6m1^2 )
-2/6 = -1/3
a= g*(-1/3)

and what is meant by m1 is much larger than m2 and m3 ?

(e) if m1=m2=m3

i'll convert everything to m1

a= g(3m1m1-4m1m1-m1m1)/(m1m1+m1(4m1+m1)

simplifying (3m1^2 -4m1^2-m1^2)/(m1^2+4m1^2+m1^2)
(-2m1^2)/(6m1^2 )
-2/6 = -1/3
a= g*(-1/3)

and what is meant by m1 is much larger than m2 and m3
That looks right.

m1 is much larger than m2 means you can neglect m2 when you are performing operations such as addition or subtraction with m1 and m2.

if the title got changed it would be better to avoid confusion

jedishrfu
Mentor

(e) if m1=m2=m3

i'll convert everything to m1

a= g(3m1m1-4m1m1-m1m1)/(m1m1+m1(4m1+m1)

simplifying (3m1^2 -4m1^2-m1^2)/(m1^2+4m1^2+m1^2)
(-2m1^2)/(6m1^2 )
-2/6 = -1/3
a= g*(-1/3)

and what is meant by m1 is much larger than m2 and m3 ?
m1 >> m2 means that whenever you're adding m1 and m2 you can simply use m1 as if m2 is effectively zero.

(b)

a=g(0-4m1m3-m1m2)/(0+4m3m1+m2m1)

a= g*-1

a= -g

(b)

a=g(0-4m1m3-m1m2)/(0+4m3m1+m2m1)

a= g*-1

a= -g
That's again correct.

and when m1 is smaller than m2 and m3 is that the opposite ? we neglect m1 when doing addition and subtraction with m2 and m3 ?

(d)

a=g(3m2m1-0-m1m2)/(m2m1+m1m2)

a=g*1

a=g

LCKurtz
Homework Helper
Gold Member
And, while you're at it, each time post the problem itself along with your question instead of a pdf file.

And, while you're at it, each time post the problem itself along with your question instead of a pdf file.
Ok so i post a new reply in this thread for each problem or do i make a separate thread for each problem ?

Mark44
Mentor
Ok so i post a new reply in this thread for each problem or do i make a separate thread for each problem ?