16.1 Show that e^{2x}, sin(2x) is linearly independent on + infinity -infinity

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Discussion Overview

The discussion revolves around the linear independence of the functions \( e^{2x} \) and \( \sin(2x) \) over the interval \((- \infty, + \infty)\). Participants explore the calculation of the Wronskian as a method to demonstrate this independence, while also referencing similar functions.

Discussion Character

  • Mathematical reasoning, Homework-related, Technical explanation

Main Points Raised

  • One participant initiates the discussion by stating the problem of showing that \( e^{2x} \) and \( \sin(2x) \) are linearly independent.
  • Another participant calculates the Wronskian for \( e^x \) and \( \cos(x) \), suggesting a method for the original problem.
  • A third participant attempts to clarify the Wronskian calculation, providing a determinant expression involving \( e^x \) and \( \cos(x) \) and \( -\sin(x) \).
  • One participant expresses uncertainty about the relevance of their previous post, indicating a potential misunderstanding or misdirection in the discussion.

Areas of Agreement / Disagreement

The discussion reflects uncertainty and confusion regarding the calculations and relevance of the Wronskian, with no clear consensus on the approach to demonstrate linear independence.

Contextual Notes

Participants reference different functions and calculations, leading to potential limitations in the clarity of the problem being addressed. There are unresolved mathematical steps and assumptions about the functions involved.

karush
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16.1 Show that $e^{2x}$, sin(2x) are linearly independent on $(-\infty,+\infty)$

https://www.physicsforums.com/attachments/9064
that was the example but...

\begin{align*}
w(e^x,\cos x)&=\left|\begin{array}{rr}e^x&\cos{x} \\ e^x&-\cos{x} \\ \end{array}\right|\\
&=??\\
&=??
\end{align*}
 
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$$=e^x(-\cos(x)-\cos(x))=-2e^x\cos(x)\dots$$

But don't you need to calculate $w\left(e^{2x},\cos(2x)\right)?$ What do you get for that?
 
karush said:
but...

\begin{align*}
w(e^x,\cos x)&=\left|\begin{array}{rr}e^x&\cos{x} \\ e^x&-\cos{x} \\ \end{array}\right|\\
&=??\\
&=??
\end{align*}

$$w(e^x,\cos{x}) = \begin{vmatrix}
e^x & \cos{x}\\
e^x & -\sin{x}
\end{vmatrix} = -e^x(\sin{x}+\cos{x})$$
 
Sorry everybody I think this thread went off the rails
my 2nd post was way off
so Ill post another new one of a similar problem


 
Last edited:

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