16.1 Show that e^{2x}, sin(2x) is linearly independent on + infinity -infinity

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SUMMARY

The discussion focuses on demonstrating the linear independence of the functions \(e^{2x}\) and \(\sin(2x)\) over the interval \((- \infty, + \infty)\). Participants engage in calculating the Wronskian determinant, specifically \(w(e^{2x}, \cos(2x))\), to establish this independence. The Wronskian is computed as \(w(e^x, \cos x) = -e^x(\sin x + \cos x)\), indicating that these functions do not satisfy a linear combination that equals zero for all \(x\). The conversation highlights the importance of correctly applying the Wronskian method in proving linear independence.

PREREQUISITES
  • Understanding of linear independence in the context of functions
  • Familiarity with Wronskian determinants
  • Knowledge of calculus, specifically derivatives and their applications
  • Basic understanding of exponential and trigonometric functions
NEXT STEPS
  • Study the properties of the Wronskian and its role in determining linear independence
  • Explore examples of linear independence involving other exponential and trigonometric functions
  • Learn about the implications of linear independence in differential equations
  • Investigate the relationship between linear independence and function spaces
USEFUL FOR

Mathematics students, educators, and researchers interested in differential equations, linear algebra, and function analysis will benefit from this discussion.

karush
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16.1 Show that $e^{2x}$, sin(2x) are linearly independent on $(-\infty,+\infty)$

https://www.physicsforums.com/attachments/9064
that was the example but...

\begin{align*}
w(e^x,\cos x)&=\left|\begin{array}{rr}e^x&\cos{x} \\ e^x&-\cos{x} \\ \end{array}\right|\\
&=??\\
&=??
\end{align*}
 
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$$=e^x(-\cos(x)-\cos(x))=-2e^x\cos(x)\dots$$

But don't you need to calculate $w\left(e^{2x},\cos(2x)\right)?$ What do you get for that?
 
karush said:
but...

\begin{align*}
w(e^x,\cos x)&=\left|\begin{array}{rr}e^x&\cos{x} \\ e^x&-\cos{x} \\ \end{array}\right|\\
&=??\\
&=??
\end{align*}

$$w(e^x,\cos{x}) = \begin{vmatrix}
e^x & \cos{x}\\
e^x & -\sin{x}
\end{vmatrix} = -e^x(\sin{x}+\cos{x})$$
 
Sorry everybody I think this thread went off the rails
my 2nd post was way off
so Ill post another new one of a similar problem


 
Last edited:

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