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A 123 kg chesterfield is pushed up a frictionless ramp at a constant speed by a delivery person.

If the ramp is inclined at 26.9° to the horizontal, what horizontal force must the delivery person apply to the chesterfield?

http://capa.physics.mcmaster.ca/figures/hr/Graph05/hr-pic0563.png [Broken]

The way I am thinking about the problem is that the answer should be the horizonal component of the F(g) (weight) of the chesterfield (C). Since balancing that force would produce a net force of 0 in the horizontal dimension.

Drawing it out, the y' of w is wcosθ and x' is wsinθ. So the horizonal component would be (wsinθ)cosθ. The number I get for that is486.85N(using g=9.81). This is apparently incorrect.

So my question is: How am I supposed to think about this problem? What am I doing wrong? Also, the question seems a little ambiguous also, but how would any of you interpret it?

Thank you for your time and consideration.

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# Homework Help: 2-D kinematics/Forces (weight up an incline)

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