- #1
ubbaken
- 8
- 0
The Question:
A 123 kg chesterfield is pushed up a frictionless ramp at a constant speed by a delivery person.
If the ramp is inclined at 26.9° to the horizontal, what horizontal force must the delivery person apply to the chesterfield?
http://capa.physics.mcmaster.ca/figures/hr/Graph05/hr-pic0563.png
The way I am thinking about the problem is that the answer should be the horizonal component of the F(g) (weight) of the chesterfield (C). Since balancing that force would produce a net force of 0 in the horizontal dimension.
Drawing it out, the y' of w is wcosθ and x' is wsinθ. So the horizonal component would be (wsinθ)cosθ. The number I get for that is 486.85N (using g=9.81). This is apparently incorrect.
So my question is: How am I supposed to think about this problem? What am I doing wrong? Also, the question seems a little ambiguous also, but how would any of you interpret it?
Thank you for your time and consideration.
A 123 kg chesterfield is pushed up a frictionless ramp at a constant speed by a delivery person.
If the ramp is inclined at 26.9° to the horizontal, what horizontal force must the delivery person apply to the chesterfield?
http://capa.physics.mcmaster.ca/figures/hr/Graph05/hr-pic0563.png
The way I am thinking about the problem is that the answer should be the horizonal component of the F(g) (weight) of the chesterfield (C). Since balancing that force would produce a net force of 0 in the horizontal dimension.
Drawing it out, the y' of w is wcosθ and x' is wsinθ. So the horizonal component would be (wsinθ)cosθ. The number I get for that is 486.85N (using g=9.81). This is apparently incorrect.
So my question is: How am I supposed to think about this problem? What am I doing wrong? Also, the question seems a little ambiguous also, but how would any of you interpret it?
Thank you for your time and consideration.
Last edited by a moderator: