The Question: A 123 kg chesterfield is pushed up a frictionless ramp at a constant speed by a delivery person. If the ramp is inclined at 26.9° to the horizontal, what horizontal force must the delivery person apply to the chesterfield? http://capa.physics.mcmaster.ca/figures/hr/Graph05/hr-pic0563.png [Broken] The way I am thinking about the problem is that the answer should be the horizonal component of the F(g) (weight) of the chesterfield (C). Since balancing that force would produce a net force of 0 in the horizontal dimension. Drawing it out, the y' of w is wcosθ and x' is wsinθ. So the horizonal component would be (wsinθ)cosθ. The number I get for that is 486.85N (using g=9.81). This is apparently incorrect. So my question is: How am I supposed to think about this problem? What am I doing wrong? Also, the question seems a little ambiguous also, but how would any of you interpret it? Thank you for your time and consideration.