- #1
bennyska
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- 0
Homework Statement
so, problem 1:
xy' + 2y = 6x2y1/2
Homework Equations
so this is a bernoulli, where, in the form y' + p(x)y = q(x)yn
The Attempt at a Solution
xy' + 2y = 6x2y1/2
y' + (2/x)y =6xy1/2
so in the form, p(x) = 2/x, q(x) = 6x, and v = y1/2
dividing both sides by y1/2
y-1/2y' + (2/x)y1/2 = 6x
substitute v = y1/2 and simplify
this becomes:
2dv/dx + (2/x)v = 6x
dv/dx + (1/x)v = 3x
this is linear, and let mu(x)= eint. 1/x dx = eln x = x
multiply both sides, and get
d/dx(xv) = 3x2
integrate
xv = x3 + c0
v = x2 + c0/x
replace v
y1/2 = x2 + co/x
y = (x2 + c0/x)2
here's the problem. when i do this without the constant of integration, it works fine, i.e. (x2)2 is a valid solution. so I've gone over this several times, but can't find my mistake. any help?
problem no 2: i can't get started. a point in the right direction would be appreciated.
ex+ y*exy + (ey+ x*eyx)y'=0
as i type it, i wonder if i copied something down wrong, having the yx in reverse alphabetical order. oh well, yeah, a pointer would help. thanks!