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hey guys ok basically i have 2 questions, first one is

(1) "find the point on the curve y=(x-1)[power of 5] +2 where the tangent to the curve at these points is parallel to the x axis"

Attempt : well the gradiet of the x axis is 0. So i differentiated the equation and i got myself

y'=5(x-1)[power of 4] +2 and then i substutitued 0 into y and then used the solver funnction in my calculator but its giving me x = 101.something

The answer is ment to be (1,2)

(2) for this question i just want to know the general process of how i would find the points of intersection between a quadratic and a linear equation , as well between 2 quadratic equations. ( you are provided the equation of the curve/line)

thanks

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# Homework Help: 2 questions - applicable differenation and intersection

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