2 questions--seems simple -- Heisenberg Uncertainty

[fu11meta1]

Homework Statement

These questions are out of Modern Physics by Tipler. I feel like I'm close to the answer but missing something small.

#1: A ladybug 5mm in diameter with a mass of 1 mg being viewed through a low power magnifier with a calibrated reticule is observed to be stationary with an uncertainty of 10^-2 mm. How fast might the ladybug actually be walking?

#2 Protons and neutrons in nuclei are bound to the nucleus by exchanging pions ( pi mesons) with each other. This is possible to do without violating energy conservation provided the pion is reabsorbed within a time consistent with the Heisenberg uncertainty relations. Consider the emission reaction p --> p + where m = 135 MeV/c2.

A: Ignoring kinetic energy, by how much is energy conservation violated in this reaction?
B: Within what time interval must the pion be reabsorbed in order to avoid the violation of energy conservation?

Homework Equations

ΔXΔP ≥ ħ/2
ΔE*τ ≥ ħ

The Attempt at a Solution

For #1:
I said that since the uncertainty is .01mm the lower boundary(lowest possible measurement for the diameter) is (5 - .01)mm and the upper boundary is (5+.01)mm. so:

ΔP≈ ħ/2(ΔX) (For both X's. You'll get 2 values for P)

Then saying P=MV. so V ≈ ħ/2(M)(ΔX) for both X's.

For #2:
I said that the conservation is violated by the rest energy of one pion. Because p ---> p + π is the reaction.

but I'm not sure what to use for the uncertainty for E (ΔE) in:
τ ≥ ħ/ΔE

My best! Thanks!

 

[Simon Bridge]

#2: what kinds of energy are you being told about?
just looking at the equation - what is the change in energy?

#1: Δx is the uncertainty in position - not an actual position.

 

[fu11meta1]

I see! Thanks for your help. I read some more into it and found that it is the uncertainty. As for #2 it 135 MeV(pion). for ΔE