- #1
force
What is the difference between a differential and a derivative ?
(SQR[9 - x^2])^2 = 9 - x^2 ok, so what is SQR[9 - x^2] = ?
(SQR[9 - x^2])^2 = 9 - x^2 ok, so what is SQR[9 - x^2] = ?
Well, you could factor it to [itex]\sqrt{9 - x ^ 2} = \sqrt{(3 - x)(3 + x)}[/itex]force said:well could you factor or simplify this expression SQR[9 - x^2] any further ?
The bolded part is wrong, it should read: dy = f'(x) dx.force said:consider y=f(x)= x^3 +3x
dy/dx=3x^2+3 is its derivative with respect to x, then what is its differential dy=f(x) dx ?
Err, I don't get this. Can you clarify it please...roger said:x^2 can't be bigger than or equal to 0 as you already stated x[itex] forall x \in \mathbb{R}[/itex]
I didn't state that the domain, or the codomain, or even the image is the real! I stated that the domain is [-3; 3] (post #3).roger said:you stated that the domain / range was the reals so x^2 can't be bigger than 9
Uhmm, as I interprete, the OP might be asking for the image of the function: [itex]\sqrt{9 - x ^ 2}[/itex] if the following condition is met:roger said:That's alright. It was a misunderstanding. I don't understand the relevance of this though, to what the OP asked ?
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