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2nd Order In-Homogeneous Particular Solution?

  1. May 26, 2013 #1
    Did it :)
    Last edited: May 26, 2013
  2. jcsd
  3. May 26, 2013 #2


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    Yes, the characteristic equation is [itex]r^2+ 4r+ 3= (r+ 3)(r+ 1)= 0[/itex] which has roots r= -1 and r= -3 so the general solution to the associated homogeneous equation is [itex]Ae^{-3x}+ Be^{-x}[/itex].

    For [itex]2e^{2x}cos(x)[/itex] try [itex]e^{2x}(Ccos(x)+ Dsin(x)[/itex]. For ##3xe^{-4x}##, try [itex]e^{-4x}(Ex+ F)[/itex]. For 3, try G.
    Last edited by a moderator: May 26, 2013
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