3 dimensional vector problem .

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To prove that cos a = Rz/R, where a is the angle between vector Rz and R, start by considering the vectors Rx, Ry, and Rz as perpendicular components of vector R. Construct a right triangle with R as the hypotenuse and Rz as one leg, while the other leg is the resultant of Rx and Ry. Using trigonometric relationships, the cosine of angle a can be expressed as the ratio of the adjacent side (Rz) to the hypotenuse (R). Alternatively, the dot product can be applied, utilizing the definitions of the dot product and the relationship between the vectors to derive the angle. This approach confirms the relationship between the components and the angle as required.
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Homework Statement


Given a vector R=Rx + Ry + Rz , prove that the cos a = Rz/R where a is the angle between vector Rz and R .


Homework Equations


I just don't know how to start .


The Attempt at a Solution

 
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Your notation isn't totally clear, but I'll assume you mean Rx, Ry and Rz to be perpendicular to each other. Then draw a triangle with sides R, Rz and Rx+Ry. Since Rz and Rx+Ry are perpendicular to each other this is a right triangle. And R is the hypotenuse. Now use trig.
 
Another way is to use the dot product, if you have had that in class. One definition of \vec{u}\cdot\vec{v} is |\vec{u}||\vec{v}|cos(\theta) where \theta is the angle between \vec{u} and \vec{v}. Another, equivalent, definition is that the dot prouct of u_x\vec{i}+ u_y\vec{j}+ u_z\vec{k} and v_x\vec{i}+ v_y\vec{j}+ v_z\vec{k} is u_xv_x+ u_yv_y+ u_zv_z. comparing those should give you then angle between R_x\vec{i}+ R_y\vec{j}+ R_z\vec{k} and R_x\vec{i}.
 
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