3 masses and an inclined pulley system

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SUMMARY

The discussion focuses on calculating the tension in a pulley system involving a 6 kg and a 4 kg mass, with a net force of 40 N and a kinetic friction coefficient of 0.4. The correct approach involves applying Newton's Second Law, where the net force must account for all acting forces. The calculated tension of 27.4 N is incorrect as it does not consider the mass of the 4 kg object or the effects of friction. A proper reevaluation of the forces and acceleration is necessary for accurate results.

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  • Understanding of Newton's Second Law of Motion
  • Basic knowledge of friction coefficients and their impact on motion
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  • Review the principles of Newton's Second Law and its application in multi-body systems
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Hdfjgf

Homework Statement


The tension between the 6 kg and 4 kg object
x5gnc-jpg.jpg

as=2.1m/s
Fnet = 40N
assume 0.4 kinetic friction coefficent

Homework Equations


T1- Fnet = mas

The Attempt at a Solution


acceleration is negative because the object is decelerating as it goes up the slope
so T1-40N = 6(-2.1)
T1 = 27.4 N
So is this right is the tension 27.4 N or do we have to include the mass of the 4kg object in the equation
 
Last edited by a moderator:
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Hdfjgf said:
T1- Fnet = mas
Newton's 2nd law says Fnet = ma where Fnet is the sum of all the forces. Your equation does not make sense. You must first add all the forces to get the net force, then you set what you get equal to mass times acceleration.

Also, it would help us help you if you quoted the problem exactly as it was given to you.
 
Hdfjgf said:
assume 0.4 kinetic friction coefficient
The acceleration you calculated seems to have ignored this.
Once you have the correct acceleration, just consider the forces on the 6kg mass.
As with kuruman, I cannot make sense of your Fnet equation.
 

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