3 vectors using south, northeast, and west

  • Thread starter Thread starter chocolatelover
  • Start date Start date
  • Tags Tags
    Vectors
Click For Summary

Homework Help Overview

The problem involves calculating the resultant displacement of a particle undergoing three consecutive displacements: 3.80 m south, 8.40 m northeast, and 14.0 m west. The context is rooted in vector addition and the representation of vectors in a two-dimensional plane.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the correct representation of the vectors in terms of their components, questioning the use of the law of cosines and the need for diagrams. There is also exploration of how to calculate the resultant vector and its magnitude, with some participants suggesting drawing diagrams and measuring angles.

Discussion Status

The discussion is active, with participants providing insights into vector components and the need for proper notation. Some guidance has been offered regarding the representation of the northeast vector and the addition of components, but there is no explicit consensus on the final calculations or methods.

Contextual Notes

Participants note the importance of correctly identifying the direction of vectors and the implications of using negative components for south and west directions. There is also mention of potential confusion regarding the northeast vector's components and the need for clarity in the problem setup.

chocolatelover
Messages
238
Reaction score
0
[SOLVED] 3 vectors using south, northeast, and west

Homework Statement


A particle undergoes the following consecutive displacements: 3.80 m south, 8.40 m northeast, and 14.0 m west. What is the resultant displacement?


Homework Equations





The Attempt at a Solution



This means that I have 3.80j, 8.4i, and 14.0k, right? I could then add up all of the x components and y components, right? or do I need to use the law of cos?

thank you very much
 
Physics news on Phys.org
No. This is a 2D problem. Conventionally you would have -3.8j for south and -14.0i for west. North East will be a vector of components of i and j. Try drawing a diagram to help you.
 
Thank you very much

I drew a diagram, but the triangle does not seem to be a perfect right triangle. Wouldn't I also have 8.4k? Could you tell me what formula I would need to solve this problem? or would I need to draw it out on graph paper and measure the angles?

Vector A would be (0i+3.8j),vector B would be 8.4k , and vector C would be (14.03i+oj), right? or is the 8.4 part extra information that it is not needed?

I added up the components and got:

Vector A+B=14.03i+3.8j

R=square root of (14.03)^2+(3.8)^2=14.5

Does that look correct? How would I go about solving for the angle?

Thank you
 
Last edited:
The northeast vector will have i and j components. Northeast indicates the vector is 45 degrees north of east, so the components will be equal.

The other two vectors will have negative components in standard notation since i is taken to be the direction east and j is taken to be in the north direction.

Then one will use vector addition to find the resultant displacement.
 
Thank you very much

I found the x and y components of the northeast vector to be 5.9. I then added up the i's and j's and got 19.93 for the i's and 9.7 for the j's.

Magnitude=square root (19.93)^2+(9.7)^2=22.2

direction=45°

Does that look right?

Thank you very much
 
South and west are negative, so for the i's it would be 5.9 + (-14.0) etc.
 
Thank you very much

Regards
 

Similar threads

Replies
28
Views
3K
Replies
6
Views
5K
  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 19 ·
Replies
19
Views
8K
Replies
3
Views
2K
  • · Replies 38 ·
2
Replies
38
Views
8K
  • · Replies 9 ·
Replies
9
Views
2K
Replies
8
Views
1K
Replies
2
Views
5K
  • · Replies 7 ·
Replies
7
Views
4K