# Homework Help: 58th derivative of (1+x^3)^30 at x=0

1. Nov 7, 2013

### freshman2013

1. The problem statement, all variables and given/known data

find the 58th derivative of (1+x^3)^(30) at zero (The Answer is zero)

2. Relevant equations

The binomial series expansion
the maclaurin series (f^(n)(0)/n!)x^n

3. The attempt at a solution
So I expanded the given equation into the binomial series and at at the 19th term, I got 30(30-1)...(30-19+1)/57! * x^(57). But I don't get how that gets me any closer to the answer of zero.

2. Nov 7, 2013

### Dick

First just figure out what powers of x could have a nonzero 58th derivative at zero. Try a few.