A 6kg box is placed on a 32degree frictionless ramp. Find accel. of the box.

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SUMMARY

The discussion focuses on solving the acceleration of a 6kg box placed on a 32-degree frictionless ramp using force components. The key equation derived is Fx = max, where Fx represents the force in the x direction, and ax is the acceleration. The force component acting down the ramp is calculated as mg sin(32°), which directly influences the box's acceleration. Participants emphasize the importance of choosing the correct coordinate system to simplify the problem-solving process.

PREREQUISITES
  • Understanding of Newton's Second Law (F = ma)
  • Basic trigonometry for resolving forces into components
  • Knowledge of gravitational force calculations (mg)
  • Familiarity with inclined plane physics
NEXT STEPS
  • Study the concept of force components on inclined planes
  • Learn about vector resolution in physics
  • Explore examples of frictionless surfaces in mechanics
  • Investigate the effects of different angles on acceleration in inclined planes
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Kaxa2000
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I have the solution to the problem but I don't get the part how you rotate the axes and then solve from there.

For example in the x direction
Fx = max

+mg sin32 = max

Fx = Force in x direction
ax = acceleration in the x direction

Can someone explain this?
 
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You're taking the component of the weight vector down the ramp. That is the force that accelerates the box.
 
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Hi Kaxa2000! Welcome to PF! :smile:
Kurdt said:
You're taking the component of the weight vector down the ramp. That is the force that accelerates the box.

I'll just add that you shouldn't think of it as a rotation …

everything stays as it is, and you simply choose to take components in whatever direction is most conveniento:)

for example, you could use horizontal and vertical components …

but that would give you two equations :redface:, while choosing along-the-ramp and normal gives you only one relevant equation, which is much easier! :wink:
 

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