Albert1
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$ABCD$ is a Cyclic quadrilateral,given $BC=CD$
Prove:
$AC^2=AB\times AD+BC^2$
Prove:
$AC^2=AB\times AD+BC^2$
hint:Albert said:$ABCD$ is a Cyclic quadrilateral,given $BC=CD$
Prove:
$AC^2=AB\times AD+BC^2$