A ball bounces off a brick wall, Find the average acceleration

Click For Summary

Homework Help Overview

The discussion revolves around a physics problem involving a Super Ball bouncing off a brick wall. The problem requires calculating the average acceleration of the ball given its initial and final velocities, as well as the time of contact with the wall.

Discussion Character

  • Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants explore the correct formulation for average acceleration, questioning the signs of the velocities based on the direction of motion. There is discussion about the implications of a perfect bounce versus a real bounce with speed loss.

Discussion Status

Some participants have provided calculations and expressed confusion regarding the correct approach to determining average acceleration. There is a mix of attempts to clarify the reasoning behind the signs used in the equations, with some guidance offered on significant figures in the results.

Contextual Notes

Participants are operating under the constraints of the problem as stated, including the mass of the ball, its velocities before and after the impact, and the time of contact with the wall. There is an emphasis on the assumptions related to directionality and the nature of the bounce.

Alexanddros81
Messages
177
Reaction score
4

Homework Statement


Serway Physics Section 2.4 Acceleration

14. A 50.0-g Super Ball traveling at 25.0 m/s bounces off a brick wall and rebounds
at 22.0 m/s. A high-speed camera records this event. If the ball is in contact with the
wall for 3.50 ms, what is the magnitude of the average acceleration of the ball during
the time interval?

Homework Equations

The Attempt at a Solution



I am a bit confused with this one.

If the ball is moving to the right before it hits the wall with a speed of 25.0 m/s and after the rebound
is moving to the left with a speed of 22.0 m/s then should it be:

##a_{avg} =\frac {-22.0 m/s - 25.0 m/s)} {0.0035 s} ##

or

##a_{avg} = \frac {22.0 m/s - 25.0 m/s} {0.0035 s}##

(taking the x positive direction to the right)

thanks
 
Physics news on Phys.org
Alexanddros81 said:
If the ball is moving to the right before it hits the wall with a speed of 25.0 m/s and after the rebound
is moving to the left with a speed of 22.0 m/s then should it be:

##a_{avg} =\frac {-22.0 m/s - 25.0 m/s)} {0.0035 s} ##

or

##a_{avg} = \frac {22.0 m/s - 25.0 m/s} {0.0035 s}##

(taking the x positive direction to the right)

thanks
What thought experiment might you apply to choose between them? Suppose that the bounce was perfect instead of losing a bit of speed. Which formula would give a reasonable result?
 
Alexanddros81 said:

Homework Statement


Serway Physics Section 2.4 Acceleration

14. A 50.0-g Super Ball traveling at 25.0 m/s bounces off a brick wall and rebounds
at 22.0 m/s. A high-speed camera records this event. If the ball is in contact with the
wall for 3.50 ms, what is the magnitude of the average acceleration of the ball during
the time interval?

Homework Equations

The Attempt at a Solution



I am a bit confused with this one.

If the ball is moving to the right before it hits the wall with a speed of 25.0 m/s and after the rebound
is moving to the left with a speed of 22.0 m/s then should it be:

##a_{avg} =\frac {-22.0 m/s - 25.0 m/s)} {0.0035 s} ##

or

##a_{avg} = \frac {22.0 m/s - 25.0 m/s} {0.0035 s}##

(taking the x positive direction to the right)

thanks

Can't you tell that your second aavg is wrong? 22.0 m/s is to the left, so why is it positive?

Zz.
 
  • Like
Likes   Reactions: Alexanddros81
Here is my solution:

Serway Physics 2_14001.jpg


Is this ok?
 

Attachments

  • Serway Physics 2_14001.jpg
    Serway Physics 2_14001.jpg
    13 KB · Views: 1,342
Alexanddros81 said:
[...] 25.0 m/s [...] 22.0 m/s [...] 50.0 g Super Ball [...] 3.50 ms [...] -13428.57 m/s2 [...]
Is this ok?
The calculation looks fine. Carrying seven significant figures in a result obtained from inputs with only three significant figures is excessive.
 

Similar threads

Replies
1
Views
2K
Replies
9
Views
3K
Replies
16
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 4 ·
Replies
4
Views
6K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 5 ·
Replies
5
Views
6K
  • · Replies 9 ·
Replies
9
Views
4K
Replies
1
Views
2K
  • · Replies 23 ·
Replies
23
Views
5K