- #1

234jazzy2

- 11

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## Homework Statement

A 0.5 kg ball is swung in a circular path from a 80 cm long rope, attached to a vertical pole.

A. What is the speed of the ball theta (between the pole and rope) is 40 deg?

B. What is the KE of the ball at theta = 40 deg?

C. The ball slows down and the KE drops to 50% of the value in (B). What is the new value of theta?

## Homework Equations

F = ma

centripetal acceleration = V^2/r

## The Attempt at a Solution

A.

Fy = 0

Tcos(theta) = mg

Fx = mv^2/r

Tsin(theta) = mv^2/r - > V = sqrt(g*r*tan(theta)) = 2.056 m/s

B. KE = 0.5 *m*v^2 = 1.057151179

C. I get all the have to new velocity but i don't know how to get the angle... I need some pointers.

Also, i am not sure if this is the right approach.

Thanks