A bit introduction to foliation in GR and some question.

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SUMMARY

This discussion focuses on the application of the Einstein-Hilbert Lagrangian, specifically the formulation of the Lagrangian as \(\mathcal L = (-g)^{1/2}R\) and its decomposition into components involving the lapse function \(N(t)\). The author explores the implications of splitting the metric \(g_{ab}\) and how it relates to the energy density equation \(R_{00} = T_{00} = \rho\). Key insights include the relationship between the Ricci tensor in three-dimensional intrinsic geometry and its restriction to the hyperslice, emphasizing the distinction between kinetic and potential energy terms in the Lagrangian formulation.

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  • Understanding of General Relativity concepts, particularly the Einstein-Hilbert action.
  • Familiarity with the Ricci scalar and Ricci tensor in differential geometry.
  • Knowledge of the lapse function and its role in the ADM formalism.
  • Basic principles of tensor calculus and spacetime metrics.
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  • Study the ADM decomposition of spacetime and its implications in General Relativity.
  • Learn about the role of the Ricci tensor in the Einstein field equations.
  • Explore the concept of energy density in the context of General Relativity.
  • Investigate the relationship between kinetic and potential energy in Lagrangian mechanics.
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This discussion is beneficial for theoretical physicists, graduate students in physics, and researchers focusing on General Relativity and gravitational theories. It provides insights into advanced concepts of Lagrangian mechanics and the geometric interpretation of spacetime.

Kevin_spencer2
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If we have Einstein-Hilbert Lagrangian so:

[tex]\mathcal L = (-g)^{1/2}R[/tex] for R Ricci scalar (¿?) then my question perhaps mentioned before is if we can split the metric into:

[tex]g_{ab}= Ndt^{2}+g_{ij} dx^{i} dx^{j}[/tex] N=N(t) 'lapse function'

then i would like to know if somehow you can split the Lagrangian into:

[tex]\mathcal L = (-g)^{1/2}R=N^{1/2}(g^{3})^{1/2}g^{00}R_{00}+N^{1/2}(g^{3})^{1/2}g^{ij}R_{ij}[/tex]


Following Einstein equations then [tex]R_{00}=T_{00}= \rho[/tex] 'energy density equation' and

[tex]\iiint (g^{3})^{1/2}R^{(3)}d^{3}x = 2T[/tex]

[tex]\iint (g^{(3)})^{1/2}R_{00}=\mathcal H = E[/tex]

Is some kind of Kinetic energy so the Einstein-Hilbert Lagrangian takes the form:

[tex]\mathcal L =\int_{a}^{b} dt(T-V)[/tex] a Kinetic plus potential term.
 
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For one thing, the Ricci tensor computed from the (three-dimensional) intrinsic geometry of the hyperslice is not the same as the restriction of the Ricci tensor (computed for the spacetime itself) to said hyperslice.
 

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