A car speeding up from rest to constant accel. travels 130m in 6s. How far in

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A car accelerates from rest and covers 100 meters in 6.04 seconds, prompting a calculation for the distance traveled in the first 2.37 seconds. The initial approach involves calculating average velocity by dividing total distance by total time, resulting in 16.5 m/s. However, using this average velocity to find distance for the first 2.37 seconds yields an incorrect result. Suggestions include drawing a velocity vs. time graph to better understand the acceleration and calculate the distance accurately. The discussion emphasizes the importance of proper calculations and graphical representation in solving motion problems.
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A car speeding up from rest to constant accel. travels 100 meters in 6.04s. How far did it travel in the first 2.37 seconds?

So I figure if I divide distance by time 100/6.04 it will give me the velocity 16.5m/s. And since distance = vt I would do d=15.6*2.37 which equals 37.03m but this is wrong. I was also told to try drawing a graph of velocity vs time...but how can I graph numbers such as these (high and low #'s with decimals) If I can't graph it I can't find the slope or y intercept...so I'm lost
 
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Draw a graph of velocity vs. time.
Distance travelled=velocity x time
 

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