A child pulls a wagon (find Tension)

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SUMMARY

A child pulls an 11 kg wagon and a 1.4 kg handle, accelerating both at 2.4 m/s². According to Newton's Second Law of Motion, the tension in the rope near the child is calculated to be 3 N, while the tension near the wagon is 30 N. The vertical forces are balanced, indicating no vertical acceleration, and the net horizontal force is determined by the mass of the handle and wagon combined. The discussion clarifies the relationship between the forces exerted by the child, the handle, and the wagon.

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Homework Statement



A child pulls an 11 kg wagon with a horizontal handle whose mass is 1.4kg , accelerating the wagon and handle at 2.4m/s^2 .

Mass of the wagon: 11 kg
Mass of the handle: 1.4kg
wagon acceleration: 2.4m/s^2
handle acceleration: 2.4m/s^2

Homework Equations


Newton's Second Law of Motion says sum of all force has the same value of the object's mass * object's acceleration

The Attempt at a Solution


tension.png


T = 3N is the tension of the rope near the child
T = 30N is the tension of the rope near the wagon

I need feedback and hints.
 
Last edited:
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I assume by "rope" you mean handle?

How would the force increase further away from the handle?

The vertical forces balance since there is no acceleration in the vertical direction: N + mg = 0

The net horizontal force on any part = ma where m is the mass of that part. That force is provided by the child to the handle. The handle mechanically applies a part of that force to the wagon. So the force on the handle and wagon is mhandle+wagona. The force on the wagon only (ie the force exerted by the handle on the wagon) is mwagona.

AM
 

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