A contradiction of the equivalence principle?

[jeff einstein]

here:

 

[jeff einstein]

Yes, you are correct.

You can convert F=ma to a=F/m.

For a given F: If m is small, then a is large. If m is large, then a is small.Looked at another way: Newton's first law says the F is equal and opposite, so
m₁a₁ = m₂a₂

And again, if m₁ is smaller than m₂, then a₁ will have to be larger than a₂

so sir i was right from the start i have tried to prove my point that different masses have different accelerations when dropped at same height

 

[jeff einstein]

am i right?

 

[Dale]

No. Different masses do not have different accelerations.

We have already covered this

 

[Vanadium 50]

Jeff, are you even considering the messages you are getting? You respond within seconds and we are covering the same ground over and over and over.

 

[jeff einstein]

Yes, you are correct.

You can convert F=ma to a=F/m.

For a given F: If m is small, then a is large. If m is large, then a is small.Looked at another way: Newton's first law says the F is equal and opposite, so
m₁a₁ = m₂a₂

And again, if m₁ is smaller than m₂, then a₁ will have to be larger than a₂

but if this is true....

 

[jeff einstein]

disprove this i guess...

 

[DaveC426913]

disprove this i guess...

Sorry, we are now mixing up two things. I may be culpable for that.

Two different masses both being under the influence of the same gravity will have the same acceleration. (1)

But that's not the scenario you have diagrammed, above. The scenario you have diagrammed is about different masses under the influence of different gravity (i.e. each others'). (2)

 

[Dale]

but if this is true....

disprove this i guess...

You have been instructed by multiple people over multiple pages carefully explaining the situation. Carefully and repeatedly explaining where your original statements were wrong and also where they were almost right. With multiple corrections from multiple people carefully explaining the physics and the source of the confusion.

Then one single person gives one single confused answer after telling you that they were confused because of a mistaken crop, and immediately you just throw out everything you were taught by all of the previous people?

That shows that you are not seeking to learn, you are just seeking validation.

Thread closed. This topic has been done. Do not re-open, just re-read.

 

[bhobba]

The acceleration of both objects, however, is not the same, because it is the force divided by the mass of the object.

I know the topic is closed, and the OP has probably not done enough math yet to understand the full answer, but this is the so-called two-body problem:

https://en.wikipedia.org/wiki/Two-body_problem

I post it to stimulate the study of vector calculus and its applications in the future.

Way back when I studied vector calculus, this important application, interestingly, wasn't covered

Strang's calculus textbook is a good place to learn it:
https://ocw.mit.edu/ans7870/resources/Strang/Edited/Calculus/Calculus.pdf

Thanks
Bill