PeroK said:
If you dropped an object of mass 1kg from the same distance as the Moon, then it would take a certain time to fall to half that distance.
If the Moon were released from rest at the same distance from Earth, then:
a) It would move half that distance in less time than the 1kg object.
b) The Earth would also have moved significantly, so the overall distance between the Moon and the Earth would be less than half the original distance at that time.
This way of describing it might be confusing since there are multiple "distances" being mixed together.
Let's try a simpler scenario: two equal masses ##m## starting from rest separated by a distance ##r##, using a barycentric coordinate system, so the origin of coordinates is halfway between the masses. This spatial origin is also where the masses will collide with each other, ending the experiment. The question is, what time will it take for them to collide?
Since the situation is symmetric, we can just consider one mass. Its acceleration, from previously given equations, is ##G m / r^2##. Notice that this acceleration
depends on the mass ##m## (since both masses are identical and the mass appears twice in the gravitational force formula). So the acceleration of each mass
towards the barycenter will be larger the larger the mass ##m## is. That means the time to collision, which is the time for each mass to move half the distance between them, will be shorter the larger the mass ##m## is. This last statement is independent of our choice of coordinates.
If we look at this in coordinates centered on the other mass, the coordinate acceleration at the start does not change, it's still ##G m / r^2##; but now there is a correction that has to be added because the origin of these new coordinates is itself accelerating towards the barycenter. In other words, these coordinates are not inertial, unlike the barycentric ones which are. So the starting coordinate acceleration alone does not determine the coordinate trajectory in this frame, as it does in the barycentric frame.
The qualitative logic above does not change when the two masses are unequal, as for the Earth and the Moon vs. the Earth and a 1 kg mass starting at the same distance as the Moon, but of course the numerical details will be different.