# A couple of projectile trajectory-related questions

1. Nov 6, 2008

### FlyinDutchman

First one (to check with others on whether or not it's correct, although I'm sure it's very easy)

1. The problem statement, all variables and given/known data
A vector makes an angle, theta, with the horizontal. The horizontal and vertical components of the vector will be equal in magnitude if angle theta is
Four Choices
(1) 30 degrees
(2) 45 degrees
(3) 60 degrees
(4) 90 degrees

2. Relevant equations
None I believe

3. The attempt at a solution
1. I drew out a right triangle
2. Angle theta is located at the left portion of the right triangle
3. Right angle = 90 degrees, of course
4. Two congruent angles will have congruent sides; as a result, 45 degrees is my answer (also because the two angles have to be equal and must add up to 90).

I'll add another one in a bit after I get this out of the way.

2. Nov 6, 2008

### PhanthomJay

correct. If you have additional questions, you might want to start a new post.