A doubt from rigid body dynamics

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In rigid body dynamics, the relationship between the velocity of the center of mass (vcm) and the velocity of any particle (vp) is expressed as vcm = vp + r × ω, where r is the position vector relative to the center of mass. The direction of angular velocity (ω) can be calculated using the formula ω = (v × r) / r², where v represents the linear velocity of the particle. Clarification is sought on the definition of v in this context. Understanding these relationships is crucial for analyzing motion in rigid bodies. The discussion emphasizes the importance of correctly applying these vector equations in dynamics.
vijayramakrishnan
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in rigid body dynamics is this relation between velocity of centre of mas and velocity of any particle in the rigid body correct?
vcm = vp + rXω

r is the position vector of the particle with respect to centre of mass

relations are written in vector form and also tell me how to calculate direction of ω.
 
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ω=(v × r) /r^2
 
tade said:
ω=(v × r) /r^2
what is v here sir?
 

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