A few Rotational Kinetic Energy Questions?

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SUMMARY

The discussion focuses on calculating rotational kinetic energy and power requirements for a wheel on a slope. The user correctly applies the principle of conservation of energy to find the speed of a solid wheel at the bottom of a slope, concluding that the slope angle does not affect the final speed. However, they mistakenly equate angular acceleration with angular velocity and miscalculate torque and power due to unit errors. The guidance provided emphasizes the importance of using correct units and definitions in physics calculations.

PREREQUISITES
  • Understanding of potential energy (PE = mgh) and kinetic energy (KE = 1/2mv² + 1/2Jω²)
  • Knowledge of moment of inertia and its calculation for solid objects
  • Familiarity with angular motion concepts, including angular velocity and angular acceleration
  • Basic principles of friction and its role in rolling motion
NEXT STEPS
  • Review the concept of moment of inertia for various shapes and its impact on rotational dynamics
  • Study the relationship between torque, angular acceleration, and moment of inertia
  • Learn about the effects of friction on rolling motion and how it influences energy conservation
  • Explore the calculations of power in rotational systems, focusing on the correct use of units
USEFUL FOR

Students preparing for physics exams, mechanical engineers, and anyone interested in understanding rotational dynamics and energy conservation principles.

paul9619
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Hi there,

I am currently in the middle of studying for an exam in a few weeks time. I would appreciate it if someone could just have a quick look over the following details below and see if I am along the right lines.

1. A solid wheel of mass 15Kg is at the top of a slope 1in4. The slope is 1.5m high at the top. The radius of the wheel is 0.5m. There is no friction involved.

Firstly I have to find the speed of the wheel at the bottom of the slope!

I have used PE= mgh = 220.725J I then let this sum = the KE of 1/2mv^2 + 1/2Jw^2 (J being moment of Inertia) I then manipulated the formula to find v at 4.43 m/s.

The next question asks that if the wheel did not roll on the way down would the speed be affected. I said yes and just took the KE Rotaional out of the question to find a different v.

Thirdly the question asked that if the slope was changed to 1in6 would the velocity be affected?? I answered no because the wheel would still be at the same height. Changing the slope would only chage the time it would take for the wheel to reach the bottom.

Am I along the right lines?

2. I have another question that asks how much power is required to drive a conveyor belt for the inital acceleration stage. The figures I have so far are as follows.

w= 6 rads/s, Pheta = 9 Rads. The initial angular acceleration is 2 rads/s. The wheel has a diameter of 0.4meters and a mass of 50kg. The belt has no mass.

Firstly I worked out KE rotational to give me 18 Joules.

Then am I right in saying that the torque is = J x angular rotation (J being Moment of Inertia). that gave me 2Newton Meters.

I then used Power = Torque x speed (I used (2Pi x w) for speed) that gave me 75.398 watts.

Am I along the right lines?

Any guidance much appreciated
 
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1. You say "there is no friction involved" but then you say the wheel rolls. The only reason it will roll is because of friction between the wheel and the slope.

You assumed the friction was large enough to make it roll without any slipping.

Apart from that, your method for finding the speed when it rolls and when it slides are OK (but I didn't check your arithmetic). You are right, the angle of the slope doesn't affect the final speed.

2. Check the units. The initial angular acceleration can't be 2 rad/s because that is an angular velocity not acceleration. It could be 2 rad/s^2.

Torque = J x angular acceleration (I'm not sure what you meant by "angular rotation"). Your answer of "2 Newton meters" seems wrong, the angular accel is 2 rad/s^2 (probably) but I don't think the wheel has J = 1.

Power = torque x angular velocity (again I'm not sure what you meant by "speed"). The angular velocities and accelerations in the question are given in rad/s and rad/s^2, so the factor of 2 pi shouldn't be in your equation.
 

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